sed如何删除匹配行和上一行

centrify

如题求解，删除匹配行和上面一行

wh7211

回复 1# centrify

1. seq 5|sed -nr ':a;$!{N;ba};s/[^\n]+\n4(\n|$)//gp'
   
2. seq 5|sed -nr '$!N;/[^\n]+\n4/d;P;D'

复制代码

输出：
1
2
5

moperyblue

1. seq 10|sed 'N;/\n.*9/d;P;D'

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csccyab

回复 2# wh7211

If the pattern is in first line, line 1 is printed.
# seq 5|sed -nr '$!N;/[^\n]+\n1/d;D'
1
2
3
4
5



What about this?

# seq 5 | sed -n '1{/1/d}; $!N; /1/d; P; D'
2
3
4
5

csccyab

回复 2# wh7211

If the pattern is in first line, first line is printed.

# seq 5|sed -nr '$!N;/[^\n]+\n1/d;D'
1
2
3
4
5


What about this?

# seq 5 | sed -n '1{/1/d}; $!N; /[^\n]+\n1/d; P; D'
2
3
4
5