如何截取两个字符串所在行中间的内容

夏寥寥

请问如何截取Fast-forward和files changed这两个字符串所在行中间的内容。多谢~~
即：

srv/sms/config/conf.toml    |  3 +++
srv/sms/config/config.go    | 15 +++++++++++----
srv/sms/handler/shortmsg.go | 10 +++++++++-
srv/sms/main.go             |  5 +++++



文件内容：

Switched to branch 'develop'
remote: Counting objects: 10, done.
remote: Compressing objects: 100% (10/10), done.
remote: Total 10 (delta 7), reused 0 (delta 0)
Unpacking objects: 100% (10/10), done.
From http://192.168.1.10
   bc1d9d5..fc8d6c7  develop    -> origin/develop
Updating bc1d9d5..fc8d6c7
Fast-forward
srv/sms/config/conf.toml    |  3 +++
srv/sms/config/config.go    | 15 +++++++++++----
srv/sms/handler/shortmsg.go | 10 +++++++++-
srv/sms/main.go             |  5 +++++
4 files changed, 28 insertions(+), 5 deletions(-)
To http://192.168.1.10
! [rejected]        bugfix/v1.6.2 -> bugfix/v1.6.2 (non-fast-forward)
! [rejected]        bugfix/v1.6.5 -> bugfix/v1.6.5 (non-fast-forward)
! [rejected]        bugfix/v1.6.6.1 -> bugfix/v1.6.6.1 (non-fast-forward)
! [rejected]        bugfix/v1.6.7 -> bugfix/v1.6.7 (non-fast-forward)
! [rejected]        bugfix/v1.6.9 -> bugfix/v1.6.9 (non-fast-forward)
! [rejected]        feature/bot -> feature/bot (non-fast-forward)
! [rejected]        feature/entsi -> feature/entsi (non-fast-forward)
! [rejected]        feature/outsoucing -> feature/outsoucing (non-fast-forward)

夏寥寥

cat 1.txt|sed -e '1,/^Fast-forward/d' -e'/files changed/,$d'

龙牙地主天

回复 1# 夏寥寥

1. awk '/Fast-forward/{p=1;next}/files changed/{p=0}p' file

复制代码

夏寥寥

回复 3# 龙牙地主天

谢谢！