shell高手指点一下，谢谢

32148501

现有一文本，内容如下
{"code": 0, "data": {"date": 1530159378260, "ticker": {"vol": "0.08531186", "low": "158", "open": "188", "high": "188", "last": "158", "buy": "122", "sell": "188"}}, "message": "OK"}
其中各项内容会变顺序，现在只想要buy和sell后面的数。怎么提出来啊。谢谢

Herowinter

感觉这个用JSON parser做更好一点

Herowinter

如果格式固定式冒号后面一个空格的话可以这样

1. buy=`grep -Po '(?<="buy": ")[0-9]+' i`;echo $buy
   
2. 122

复制代码

reyleon

对于这种JSON 数据, shell 下的 jq 工具了解一下

安装 jq

CentOS: yum -y install jq

1. [root@dxzc ~]# echo '{"code": 0, "data": {"date": 1530159378260, "ticker": {"vol": "0.08531186", "low": "158", "open": "188", "high": "188", "last": "158", "buy": "122", "sell": "188"}}, "message": "OK"}' | jq '.data'
   
2. {
   
3.   "ticker": {
   
4.     "sell": "188",
   
5.     "buy": "122",
   
6.     "last": "158",
   
7.     "high": "188",
   
8.     "open": "188",
   
9.     "low": "158",
   
10.     "vol": "0.08531186"
    
11.   },
    
12.   "date": 1530159378260
    
13. }
    
14. [root@dxzc ~]#
    
15. [root@dxzc ~]#
    
16. [root@dxzc ~]# echo '{"code": 0, "data": {"date": 1530159378260, "ticker": {"vol": "0.08531186", "low": "158", "open": "188", "high": "188", "last": "158", "buy": "122", "sell": "188"}}, "message": "OK"}' | jq '.data.ticker.buy'     
    
17. "122"
    
18. [root@dxzc ~]#

复制代码

wh7211

回复 1# 32148501

1. awk '{a["buy"];a["sell"];for(i in a){match($0,""i"[^0-9]+([^\042]+)",t);print i,t[1]}}' file
   
2. buy 122
   
3. sell 188

复制代码

christmas1102

1. perl -le '$a='sell';while(<>){m<"$a\W+\s"(.*?)">;print $1;}' 路径+文件名

复制代码

$a处修改所需字典下标

1. echo 'with open(r"路径+文件名","r+") as F:a=eval(F.read()); print(a["data"]["ticker"]["buy"])'|python

复制代码

管道符前 修改所需字典下标