bash如何提取每一行 PGID后面的数字，到数组或变量中

weichanghe2000

Hi all。请教大家一个问题，
对于下面示例给出的几行，用 bash 如何提出每一行 PGID后面的数字，到数组或变量中?
即第1行输出 11710 11712
即第2行输出 6395
即第3行输出 5027 5021 5015
用perl：
...
...

1. my @pgids;
   
2. my $a;
   
3. while ( $a =~ /PGID: (\d+);/g) {
   
4.     print "1: $1\n";
   
5.     push @pgids, $1;
   
6. }
   
7. ...
   
8. ....

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bash不知道实现??

1. Thu Jun 9 00:29:01: Resource usage collected. MEM: 3 Mbytes; SWAP: 137 Mbytes; NTHREAD: 4 PGID: 11710; PIDs: 11710 11711 11713; PGID: 11712; PIDs: 11712 11718 11719;
   
2. 
   
3. Mon Nov 29 14:08:46: Resource usage collected. MEM: 2 Mbytes; SWAP: 32 Mbytes; NTHREAD: 1 PGID: 6395; PIDs: 6395;
   
4. 
   
5. Wed Aug 13 14:23:43 2009: Started on <hostB>, Execution Home </home/user1>, Execution CWD </home/user1>; Resource usage collected. IDLE_FACTOR(cputime/runtime): 0.00 MEM: 3 Mbytes; SWAP: 4 Mbytes; NTHREAD: 3 PGID: 5027; PIDs: 5027 5028 5029; PGID: 5021; PIDs: 5021 5022 5023;  PGID: 5015; PIDs: 5015 5016 5019;
   
6. ....
   
7. ....
   
8. ....

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cfwyy

1. declare -a res
   
2. for line in `grep -Po '(?<=PGID: )\d+' file.txt`
   
3. do
   
4.         res[i]=$line
   
5.         i+=1
   
6. done

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baby_神

1. b=$(grep -Po '(?<=PGID: )[^;]+' file)
   
2. echo $b

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