从数组中取最接近已知数的元素

reb00t

1. In [22]: a = ( 37,39.1,39.2,41 )
   
2. 
   
3. In [23]: b = 38.3
   
4. 
   
5. In [24]: l = map(lambda x:abs(x-b), a)
   
6. 
   
7. In [25]: l
   
8. Out[25]: [1.2999999999999972, 0.8000000000000043, 0.9000000000000057, 2.700000000000003]
   
9. 
   
10. In [26]: a[l.index(min(l))]
    
11. Out[26]: 39.1

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wh7211

回复 1# 21002700

1. cat 1.sh
   
2. #!/bin/bash
   
3. a=( 37 39.1 39.2 41 )
   
4. b=38.3
   
5. for i in ${a[*]}
   
6. do
   
7.     if [ $(echo "${b} > ${i}"|bc) -eq 1 ];then
   
8.         c=$(echo "${b}-${i}"|bc)
   
9.     else
   
10.         c=$(echo "${i}-${b}"|bc)
    
11.     fi
    
12. 
    
13.     if [ -z "${d}" ] || [ $(echo "${c} < ${d}"|bc) -eq 1 ];then
    
14.         d=${c}
    
15.         e=${i}
    
16.     fi
    
17. done
    
18. echo ${e}
    
19. 
    
20. ./1.sh
    
21. 39.1

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