grep与正则表达式

daniey

grep ^*GET.\/\?test.HTTP file
grep ^*GET.\/\?test\/*.HTTP file

daniey

shell>awk '{if($0~/GET \/\?test HTTP/) print $0}' file
shell>awk '{if($0~/GET \/\?test\/* HTTP) print $0}' file

测试通过

bitbull

1. egrep "GET /\?test.* HTTP" file

复制代码

问题出在如果用egrep,你必须把?转义,如果用grep,不支持*表达
所以要用egrep或grep -E
PS:*不是代表任意字符,是任意个字符,所以*前面要加.(单个任意字符)
LINUX BASH测试成功

1. [root@bbhome test]# egrep "GET /\?test.* HTTP" file
   
2. afsdafa GET /?test/xxxx HTTP sddsfasf
   
3. afsdafa GET /?test HTTP sddsfasf

复制代码