时间问题

rimrock

函数time()返回的是一个整数，在我知道了mon,day,year等一些值时，如何把他们转换成类似time()返回的这个整数？

apile

1970年1月1日 使用 time()=1;
你可以換算回去.....

rimrock

不好算得，因为还有润年，比较麻烦，应该有一个函数吧？

rimrock

找到了一个函数，POSIX::mktime，但是不知道如何用？

apile

mktime
Convert date/time info to a calendar time.
Synopsis:

mktime(sec, min, hour, mday, mon, year, wday = 0, yday = 0, isdst = 0)


The month (mon), weekday (wday), and yearday (yday) begin at zero. I.e. January is 0, not 1; Sunday is 0, not 1; January 1st is 0, not 1. The year (year) is given in years since 1900. I.e. The year 1995 is 95; the year 2001 is 101. Consult your system's mktime() manpage for details about these and the other arguments.

Calendar time for December 12, 1995, at 10:30 am.

        $time_t = POSIX::mktime( 0, 30, 10, 12, 11, 95 );
        print "Date = ", POSIX::ctime($time_t);


Returns undef on failure.

muzx

那就用他了！