获取本地时间出错,请帮忙.

jerse

1. 
   
2. [root@  root]# cat time.c
   
3. #include <time.h>;
   
4. 
   
5. int
   
6. main()
   
7. {
   
8. time_t *t;
   
9. time(t);
   
10. printf(ctime(t));
    
11. }
    
12. [root@  root]$ gcc  time.c -o time
    
13. [root@ root]# ./time
    
14. Sun Mar 13 23:37:57 2016
    
15. [root@  root]# date
    
16. Tue Sep 13 10:27:27 CST 2005
    
17. [root@dev root]# hwclock -r
    
18. Tue 13 Sep 2005 10:33:15 AM CST  -0.896218 seconds
    

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这是我从文章中抄来的一段代码,在别的机器上能行,怎么在这台机器上打印出这么怪的时间来了呢?是不是库函数被篡改了?请指教,谢谢.

jerse

忘记说了,这个系统环境是:
gcc version 3.2.3 20030502 (Red Hat Linux 3.2.3-49)

renstone921

time_t *t;
time(t);

memory space?!

time zone?

1. 
   
2. /* localtime example */
   
3. #include <stdio.h>;
   
4. #include <time.h>;
   
5. 
   
6. int main ()
   
7. {
   
8.   time_t rawtime;
   
9.   struct tm * timeinfo;
   
10. 
    
11.   time ( &rawtime );
    
12.   timeinfo = localtime ( &rawtime );
    
13.   printf ( "Current date and time are: %s", asctime (timeinfo) );
    
14.   
    
15.   return 0;
    
16. }
    

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wys0436

rawtime = time(NULL)
timeinfo = localtime(&rawtime);

jerse

谢谢,我明白了,我的指针没有初始化,写成:
time_t *rawtime=(time_t *)malloc(sizeof(rawtime));
就可以了.