[目录] scandir in PHP 4.4.0

schrosource1

scandir displays files under a directory. But it is in PHP 5.
My PHP is 4.4.0. How can I handle it?


Thanks

schrosource1

The only way is write a small program:

<?php
// Note that !== did not exist until 4.0.0-RC2

if ($handle = opendir('/path/to/files')) {
   echo "Directory handle: $handle
;";
   echo "Files:
;";

   /* This is the correct way to loop over the directory. */
   while (false !== ($file = readdir($handle))) {
       echo "$file
;";
   }

   }
   closedir($handle);
}
?>;

HonestQiao

http://w.yi.org/ftp/FAPM/PHP/php_manual_zh/function.scandir.html

例子 2. scandir() 在 PHP 4 中的实现
<?php
$dir = "/tmp";
$dh  = opendir($dir);
while (false !== ($filename = readdir($dh))) {
    $files[] = $filename;
}

sort($files);

print_r($files);

rsort($files);

print_r($files);

/* Outputs something like:
Array
(
    [0] =>; .
    [1] =>; ..
    [2] =>; bar.php
    [3] =>; foo.txt
    [4] =>; somedir
)
Array
(
    [0] =>; somedir
    [1] =>; foo.txt
    [2] =>; bar.php
    [3] =>; ..
    [4] =>; .
)
*/
?>;

schrosource1

before sort.