如何在shell中将unix时间戳转换为系统时间

love100

如何在shell中将unix时间戳转换为系统时间?

如：UNIX时间1133255350

寂寞烈火

/home/lee#perl -e 'print scalar localtime(1133255350),"\n"'
Tue Nov 29 17:09:10 2005

love100

晕，原来date -r 1133255350就可以呀。

寂寞烈火

原帖由 love100 于 2005-11-29 18:36 发表
晕，原来date -r 1133255350就可以呀。

你的OS真nb,我的执行不了 :em11:

love100

localhost[/home/test] -root-#date -r 1133255350
Tue Nov 29 17:09:10 CST 2005
localhost[/home/test] -root-#

dingyi129

$ uname
FreeBSD
$ date -r 1133255350
Tue Nov 29 17:09:10 CST 2005

1.         -r seconds
   
2.              Print the date and time represented by seconds, where seconds is
   
3.              the number of seconds since the Epoch (00:00:00 UTC, January 1,
   
4.              1970; see time(3)), and can be specified in decimal, octal, or
   
5.              hex.
   

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dingyi@backup:~/manpage$ uname
Linux
dingyi@backup:~/manpage$ date -r 1133255350
date: 1133255350: No such file or directory


#uname
AIX
#date -r 1133255350
date: Not a recognized flag: r
Usage: date [-u] [+"Field Descriptors"]

[ 本帖最后由 dingyi129 于 2005-11-29 23:21 编辑 ]

寂寞烈火

GNU/Linux :

1. 
   
2. date "+%a %F %T" -d"1970-01-01 UTC 1133255350 sec"

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