字符串的计算问题

zmhjchmz

有这样一个文件内容如下，(文件名为test.txt)

1. 
   
2. 2006/08/20/04:23:21
   
3. 
   
4. Aug 20 04:03:15 linux pppd[16060]: pppd 2.4.2 started by root, uid 0
   
5. Aug 20 04:03:15 linux pppd[16060]: Using interface ppp0
   
6. Aug 20 04:03:15 linux pppd[16060]: Connect: ppp0 <--> /dev/pts/0
   
7. Aug 20 04:03:50 linux pppoe[16062]: Timeout waiting for PADO packets
   
8. Aug 20 04:03:51 linux pppd[16060]: Exit.
   
9. Aug 20 04:03:51 linux adsl-connect: ADSL connection lost; attempting re-conne
   
10. 
    
11. 2006/08/20/05:23:21
    
12. 
    
13. Aug 20 05:18:53 linux pppd[ ]: pppd 2.4.2 started by root, uid 0
    
14. Aug 20 05:18:53 linux pppd[160]: Using interface ppp0
    
15. Aug 20 05:18:53 linux pppd[4290]: Connect: ppp0 <--> /dev/pts/0
    
16. Aug 20 05:19:24 linux pppd[4290]: LCP: timeout sending Config-Requests
    
17. Aug 20 05:19:24 linux pppd[4290]: Connection terminated.
    
18. Aug 20 05:19:28 linux pppoe[4291]: Timeout waiting for PADO packets
    
19. 
    
20. 2006/08/20/05:23:28
    
21. 
    
22. Aug 20 05:18:44 linux pppd[16060]: LCP: timeout sending Config-Requests
    
23. Aug 20 05:18:44 linux pppd[16060]: Connection terminated.
    
24. Aug 20 05:18:48 linux pppoe[4269]: Timeout waiting for PADO packets
    
25. Aug 20 05:18:48 linux pppd[4268]: Exit.
    
26. Aug 20 05:18:48 linux adsl-connect: ADSL connection lost; attempting re-conne
    
27. ction.
    
28. 
    

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如果我想输出入下的结果，怎么来实现，先谢谢了
输出结果形式如下

1. 
   
2. 
   
3. 时间 （time）                      16060出现的次数              /dev/pts/0出现的次数  
   
4. 2006/08/20/04:23:21             4                                     1
   
5. 2006/08/20/05:23:21             0                                     1
   
6. 2006/08/20/05:23:28             2                                     0
   

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bwater

1. awk -v i=0 '
   
2. {if((NR-1)%9==0){i++}}
   
3. /16060/{a[i]++}
   
4. /dev/{c[i]++}
   
5. /2006\/[0-9][0-9]/{b[i]=$0}
   
6. END{for(n=1;n<=i;n++)printf "%s %d %d\n",b[n],a[n],c[n]}
   
7. ' urfile
   

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结果如下

1. 
   
2. 2006/08/20/04:23:21 4 1
   
3. 2006/08/20/05:23:21 0 1
   
4. 2006/08/20/05:23:28 2 0
   

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其它的部分\自己补上

zmhjchmz

谢谢bwater 的回复，如果用sed怎么实现