文件内容的比较判断

acxellencedk

[oracle@bdb tmp]$ cat filename1
12530999_20070301.txt
12530999_20070302.txt
12530999_20070303.txt
12530999_20070304.txt
12530999_20070305.txt
12530999_20070306.txt
12530999_20070307.txt
12530999_20070308.txt
12530999_20070309.txt
12530999_200703010.txt

[oracle@bdb tmp]$ cat filename2
12530999_20070306.txt
12530999_20070307.txt

把filename2与filename1比较， 如果filename2中的内容在filename1中存在，那么把filename1中的12530999_20070306.txt
12530999_20070307.txt
这两行去掉。并生成新的文件filename3

不知道如何实现？

寂寞烈火

try:
grep -vf fileb filea >newfile

acxellencedk

bash-2.03$ grep -vf new_filename.dat old_filename.dat >newfile
grep: illegal option -- f
Usage: grep -hblcnsviw pattern file . . .

这好像不行。

[ 本帖最后由 acxellencedk 于 2007-3-12 19:25 编辑 ]

damofeixue

$ bash --version
GNU bash, version 2.05b.0(1)-release (i386-redhat-linux-gnu)
Copyright (C) 2002 Free Software Foundation, Inc.

$ grep -vf /tmp/file2 /tmp/file1
12530999_20070301.txt
12530999_20070302.txt
12530999_20070303.txt
12530999_20070304.txt
12530999_20070305.txt
12530999_20070308.txt
12530999_20070309.txt
12530999_200703010.txt