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import socket
myname = socket.getfqdn(socket.gethostname( ))
myaddr = socket.gethostbyname(myname)
这个我在linux下只返回了'127.0.0.1'
还有一种Linux下的方法可以用的是:
Uses the Linux SIOCGIFADDR ioctl to find the IP address associated with a network interface, given the name of that interface, e.g. "eth0". The address is returned as a string containing a dotted quad.
Source: Text Source
import socket
import fcntl
import struct
def get_ip_address(ifname):
s = socket.socket(socket.AF_INET, socket.SOCK_DGRAM)
return socket.inet_ntoa(fcntl.ioctl(
s.fileno(),
0x8915, # SIOCGIFADDR
struct.pack('256s', ifname[:15])
)[20:24])
>>> get_ip_address('lo')
'127.0.0.1'
>>> get_ip_address('eth0')
'38.113.228.130' |
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