shell下怎么实现for循环的嵌套呀

daming31

如题。这个我查了很久也没查到。

ly5066113

写2个for

beauty2003

原帖由 ly5066113 于 2008-12-30 17:34 发表
写2个for

顶上去

beauty2003

for((i=0;i<=9;i++))
do
for((i=0;i<=9;i++))
do
echo "ok"
done
done

daming31

不行,是会报错的

daming31

报错如下:
[root@mail1 000tmp]# ls
aaa  bbb  ccc  key1-list  key2-list
[root@mail1 000tmp]# for i in `ls`;do echo $i"//**//";done
aaa//**//
bbb//**//
ccc//**//
key1-list//**//
key2-list//**//
[root@mail1 000tmp]# for i in `ls`; do for j in `ls /root`; do echo "------"$j;done echo $i"//**//"; done     
-bash: syntax error near unexpected token `echo'
[root@mail1 000tmp]#

我是DBA

[root@erpdataserver test]# for (( i=0;i<3;i++)); do for ((j=1;j<5;j++)); do echo $i $j ; done;done
0 1
0 2
0 3
0 4
1 1
1 2
1 3
1 4
2 1
2 2
2 3
2 4

ynchnluiti

原帖由 daming31 于 2008-12-30 17:39 发表
报错如下:
[root@mail1 000tmp]# ls
aaa  bbb  ccc  key1-list  key2-list
[root@mail1 000tmp]# for i in `ls`;do echo $i"//**//";done
aaa//**//
bbb//**//
ccc//**//
key1-list//**//
key2-list//* ...

1. for i in `ls`; do for j in `ls /root`; do echo "------"$j;done; echo $i"//**//"; done

复制代码

ynchnluiti

内部的done后少了个;

我是DBA

原帖由 daming31 于 2008-12-30 17:39 发表
报错如下:
[root@mail1 000tmp]# ls
aaa  bbb  ccc  key1-list  key2-list
[root@mail1 000tmp]# for i in `ls`;do echo $i"//**//";done
aaa//**//
bbb//**//
ccc//**//
key1-list//**//
key2-list//* ...

done后面少;