匹配删除

horizonhyg

echo "sdf,sdf,sdfZds,sfaTdsag,2012-02-09T01:01:01Z,2012-02-09T01:01:01Z,2012-02-09T02:01:01Z"
请问，如何把后边时间中的T和Z去掉呢？
我试了：sed 's/T\(.*\):/ \1:/g' 只能匹配一个，为什么不能全部替换呢？谢谢~

Shell_HAT

1. echo "sdf,sdf,sdfZds,sfaTdsag,2012-02-09T01-01-01Z,2012-02-09T01-01-01Z,2012-02-09T02-01-01Z" | sed 's/\(-[0-9][0-9]\)T\([0-9][0-9]-\)/\1 \2/g; s/\(-[0-9][0-9]\)Z/\1/g'

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昭襄王

@horizonhyg

1. $ echo "sdf,sdf,sdfZds,sfaTdsag,2012-02-09T01:01:01Z,2012-02-09T01:01:01Z,2012-02-09T02:01:01Z"|sed -r 's/([:-][0-9]{2})([TZ])/\1 /g'
   
2. sdf,sdf,sdfZds,sfaTdsag,2012-02-09 01:01:01 ,2012-02-09 01:01:01 ,2012-02-09 02:01:01
   

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horizonhyg

感谢版主！回复 2# Shell_HAT


   

horizonhyg

感谢昭襄王，都很好使，不过Z不能换成空格，要删除，T要换成空格，这个怎么办回复 3# 昭襄王


   

昭襄王

@horizonhyg分两次呗。。。。。

1. $ echo "sdf,sdf,sdfZds,sfaTdsag,2012-02-09T01:01:01Z,2012-02-09T01:01:01Z,2012-02-09T02:01:01Z"|sed -r 's/(-[0-9]{2})T/\1 /g; s/(:[0-9]{2})Z/\1/g'                        
   
2. sdf,sdf,sdfZds,sfaTdsag,2012-02-09 01:01:01,2012-02-09 01:01:01,2012-02-09 02:01:01
   

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L_kernel

horizonhyg 发表于 2012-10-08 16:16
感谢昭襄王，都很好使，不过Z不能换成空格，要删除，T要换成空格，这个怎么办回复 3# 昭襄王

1. $ echo "sdf,sdf,sdfZds,sfaTdsag,2012-02-09T01:01:01Z,2012-02-09T01:01:01Z,2012-02-09T02:01:01Z" | sed -e 's/\([0-9]\)T\([0-9]\)/\1 \2/g;s/Z\(,\|$\)/\1/g'
   
2. sdf,sdf,sdfZds,sfaTdsag,2012-02-09 01:01:01,2012-02-09 01:01:01,2012-02-09 02:01:01
   

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wuxiaobo_2009

回复 1# horizonhyg

1. [root@wuxiaobo ~]# echo "sdf,sdf,sdfZds,sfaTdsag,2012-02-09T01:01:01Z,2012-02-09T01:01:01Z,2012-02-09T02:01:01Z" | sed 's/\(-[0-9][0-9]\)T/\1 /g;s/\(:[0-9][0-9]\)Z/\1/g'
   
2. sdf,sdf,sdfZds,sfaTdsag,2012-02-09 01:01:01,2012-02-09 01:01:01,2012-02-09 02:01:01

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