请shell高手讲解一下这个函数

diedequation

stripcom() {
        local _file="$1"
        local _line

        {
                while read _line ; do
                        _line=${_line%%#*}              # strip comments
                        test -z "$_line" && continue
                        echo $_line
                done
        } < $_file
}




    _line=${_line%%#*}      
这个说是去掉注释，百思不解，还请高手指点，出自OpenBSD /etc/rc

davistar

${_line%%#*}      去掉首个出现的#以及后面的东东

lgfang

info bash

`${PARAMETER%WORD}'
`${PARAMETER%%WORD}'
     The WORD is expanded to produce a pattern just as in filename
     expansion.  If the pattern matches a trailing portion of the
     expanded value of PARAMETER, then the result of the expansion is
     the value of PARAMETER with the shortest matching pattern (the `%'
     case) or the longest matching pattern (the `%%' case) deleted.  If
     PARAMETER is `@' or `*', the pattern removal operation is applied
     to each positional parameter in turn, and the expansion is the
     resultant list.  If PARAMETER is an array variable subscripted
     with `@' or `*', the pattern removal operation is applied to each
     member of the array in turn, and the expansion is the resultant
     list.

網中人

参考一下 13 問囉：
http://bbs.chinaunix.net/viewthr ... p;page=7#pid1617953

springwind426

这个脚本有问题：

printf "#"   #print a # char

这么一行，处理后剩下什么了？