在 vi 中如何搜索换行符？

nonamed

我想在 vi 编辑器中将全部换行符替换为 x。%s/\n/x 或者 %s/^n/x 都不行，在命令行用 sed 也不行。但我在网上搜索的格式是这样的。请问在 BSD 下面应如何操作？
谢谢

jefferic

Oh, sorry, i did a mistake that the "1,$s/\n/x/g" works in VIM.
in VI, use "1,$s/$/x/g", works well.

jefferic

You did a wrong operation, the replacement command in VI is:
[line_begin],[line_end]s/[org_content]/[new_content]/[suffix]

if you want to make all "EndLine" changed into "x", it will be:
1,$s/\n/x/g
here, the applying region is all content, (from line 1 to the end);
to change any "EndLine(\n)" into character "x";
and globally do this mission(g), not just change only the first matched one.

sdkevin

/
:em11: :em11: :em11: :em11:

nonamed

原帖由 jefferic 于 2007-11-21 13:17 发表
You did a wrong operation, the replacement command in VI is:
[line_begin],[line_end]s/[org_content]/[new_content]/[suffix]

if you want to make all "EndLine" changed into "x", it will be:
1,$ ...

No match found.
除\n之外，其他都找不到。

not_halt

shell可以做到.你去shell版学下命令