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How to transfer the escape character in URL [复制链接]

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发表于 2007-10-09 17:53 |只看该作者 |倒序浏览

I’ll implement an interface. Firstly, I should implement a servlet to parse the request parameter and add the servlet configuration into web configuration. Secondly, I should deal with the logical business to implement the interface.

http://localhost:8080/yourApp/yourModule?param1=variable1%08variable2

%08 means it’s a backspace character. Some special characters should be converted to the ASCII codes with the prefix ‘%’ before they are transferred to the web server as the parameters.

public class YourServlet extends HttpServlet
{
public void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException
    {
    String variable1= request.getParameter("variable1");
    String variable2= request.getParameter("variable2");
    String remoteClientIP = request.getRemoteAddr();
   
    String result = doYourBusiness();
    response.getWriter().write(result);
    }

public void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException
    {
        doGet(request, response);
    }
}
Once you have written the servlet class, you should configure it in the web.xml.
         YourServlet
         YourServlet
        
            yourPackage.YourServlet
        
    10
        YourServlet
       / yourModule
Ok, when you restart the tomcat server, it will load an instance of YourServlet in the server context.


本文来自ChinaUnix博客,如果查看原文请点:http://blog.chinaunix.net/u/29515/showart_397351.html
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