对java代码注释的删除

way030724

代码注释删除，请高手帮忙

例如：ceshi.java

/**
* [email={@.en]{@.en[/email] Feature is father class of all the feature implementations, every feature
* hide, destroy.} [email={@.ja]{@.ja[/email] }
*
* [email={@.en]{@.en[/email] Feature is father class of all the feature implementations, every feature
* hide, destroy.} [email={@.ja]{@.ja[/email] skdjflsjdflkdjslfsjdkjflskdjfksjdlfjsldkjflksjdlkjflkjsldjflksjdsdf
* sdfdsfsdfsdfsdfsd }
*
* [email=*{@.ja]{@.ja[/email] jslkdjflkdsjlkfjldskjfkjdslfkjlsdkjflkdsjlkfjdslkjflkdsjlfkjsdlkfjslkdjflksjdlkfjsldkjfdf
* sdfsdfdsfsdfsdfsddfsdfsfdsdfsdfsdddddddddddddddddddddddddddddddddddddddd
* sdfdsfsf  }
*
* [email={@.en]{@.en[/email] Feature is father }
*
        public void hide(Hashtable paraTable) {
                currentFM.hideFeature(this, paraTable);
        }
}

规则为：1. 删除掉 [email={@.ja]{@.ja[/email] 与 紧邻下一个 } 和 之间的内容，包括这之间的描述。
          2. 删除掉 [email={@.en]{@.en[/email] 与 紧邻下一个 } ，保留这之间的英文内容。

希望得到的运行结果为：

/**
* Feature is father class of all the feature implementations, every feature
* hide, destroy.
*
* [email={@Feature]Feature[/email] is father class of all the feature implementations, every feature
* hide, destroy.
*
* [email={@Feature]Feature[/email] is father
*
        public void hide(Hashtable paraTable) {
                currentFM.hideFeature(this, paraTable);
        }
}


先行谢过拉：）

way030724

带 地址符号 '@' 问题就出错了


下面是重发的问题:

代码注释删除，请高手帮忙

例如：ceshi.java

/**
* {en Feature is father class of all the feature implementations, every fea
* hide, destroy.} {ja }
*
* {en Feature is father class of all the feature implementations, every feature
* hide, destroy.} {ja skdjflsjdflkdjslfsjdkjflskdjfksjdlfjsldkjflksjdlkjflkjsldjflksjdsdf
* sdfdsfsdfsdfsdfsd }
*
* {ja jslkdjflkdsjlkfjldskjfkjdslfkjlsdkjflkdsjlkfjdslkjflkdsjlfkjsdlkfjslkdjflksjdlkfjsldkjfdf
* sdfsdfdsfsdfsdfsddfsdfsfdsdfsdfsdddddddddddddddddddddddddddddddddddddddd
* sdfdsfsf  }
*
* {en Feature is father }
*
        public void hide(Hashtable paraTable) {
                currentFM.hideFeature(this, paraTable);
        }
}

规则为：1. 删除掉 {ja 与 紧邻下一个 } 和 之间的内容，包括这之间的描述。
          2. 删除掉 {en 与 紧邻下一个 } ，保留这之间的英文内容。

希望得到的运行结果为：

/**
* Feature is father class of all the feature implementations, every feature
* hide, destroy.
*
* Feature is father class of all the feature implementations, every feature
* hide, destroy.
*
* Feature is father
*
        public void hide(Hashtable paraTable) {
                currentFM.hideFeature(this, paraTable);
        }
}


先行谢过拉：）

lululau

你这注释怎么没有结束的地方？

way030724

不好意思啊，我不是编写java的，自己写了点代码，呵呵

/**
* {en Feature is father class of all the feature implementations, every fea
* hide, destroy.} {ja }
*
* {en Feature is father class of all the feature implementations, every feature
* hide, destroy.} {ja skdjflsjdflkdjslfsjdkjflskdjfksjdlfjsldkjflksjdlkjflkjsldjflksjdsdf
* sdfdsfsdfsdfsdfsd }
*
* {ja jslkdjflkdsjlkfjldskjfkjdslfkjlsdkjflkdsjlkfjdslkjflkdsjlfkjsdlkfjslkdjflksjdlkfjsldkjfdf
* sdfsdfdsfsdfsdfsddfsdfsfdsdfsdfsdddddddddddddddddddddddddddddddddddddd dd
* sdfdsfsf  }
*
* {en Feature is father }
*
**/

        public void hide(Hashtable paraTable) {
                currentFM.hideFeature(this, paraTable);
        }
}

lululau

1. 
   
2. liuxiang@MacBookPro: ~ $ echo '
   
3. /**
   
4. * {en Feature is father class of all the feature implementations, every fea
   
5. * hide, destroy.} {ja }
   
6. *
   
7. * {en Feature is father class of all the feature implementations, every feature
   
8. * hide, destroy.} {ja skdjflsjdflkdjslfsjdkjflskdjfksjdlfjsldkjflksjdlkjflkjsldjflksjdsdf
   
9. * sdfdsfsdfsdfsdfsd }
   
10. *
    
11. * {ja jslkdjflkdsjlkfjldskjfkjdslfkjlsdkjflkdsjlkfjdslkjflkdsjlfkjsdlkfjslkdjflksjdlkfjsldkjfdf
    
12. * sdfsdfdsfsdfsdfsddfsdfsfdsdfsdfsdddddddddddddddddddddddddddddddddddddddd
    
13. * sdfdsfsf  }
    
14. *
    
15. * {en Feature is father }
    
16. *
    
17.         public void hide(Hashtable paraTable) {
    
18.                 currentFM.hideFeature(this, paraTable);
    
19.         }
    
20. }' | perl -e '
    
21. > while(<>){
    
22. > $text .= $_;
    
23. > }
    
24. > $text =~ s/\{ja.*?\}//gs;
    
25. > $text =~ s/\{en(.*?)\}/$1/gs;
    
26. > print $text;'
    
27. 
    

复制代码

试试这个，可能会有多余空行

way030724

原帖由 lululau 于 2009-6-18 21:37 发表

liuxiang@MacBookPro: ~ $ echo '
/**
* {en Feature is father class of all the feature implementations, every fea
* hide, destroy.} {ja }
*
* {en Feature is father class of all the feature i ...

比预想的只多了一行，就像{ja jdskjfkds} 如果跨行的话，只保留一行。对吧？
下面是执行的结果，非常感谢

> print $text;'
/**
*  Feature is father class of all the feature implementations, every fea
* hide, destroy.
*
*  Feature is father class of all the feature implementations, every feature
* hide, destroy.
*
*
*
*  Feature is father
*
        public void hide(Hashtable paraTable) {
                currentFM.hideFeature(this, paraTable);
        }
}

lululau

不知道你的代码格式规范不？
如果你能保证所有的只有一个*号的注释行都顶在行首的话：

1. 
   
2. perl -e '
   
3. > while(<>){
   
4. > $text .= $_;
   
5. > }
   
6. > $text =~ s/\{ja.*?\}//gs;
   
7. > $text =~ s/\{en(.*?)\}/$1/gs;
   
8. > $text =~ s/(\*\s*\n)+/$1/gs;
   
9. > print $text;'
   

复制代码

lululau

阿，不好意思，一般来说，对于正常的Java代码，我的这个假设根本不成立阿

lululau

1. 
   
2. perl -e '
   
3. > while(<>){
   
4. > $text .= $_;
   
5. > }
   
6. > $text =~ s/\{ja.*?\}//gs;
   
7. > $text =~ s/\{en(.*?)\}/$1/gs;
   
8. > $text =~ s/([ \t]*\*\s*\n)+/$1/gs;
   
9. > print $text;'
   

复制代码

应该没问题了

way030724

标准的*号 前面还有个空格的吧？ 我在试脚本，有问题了我再给你留言吧