这个shell应该怎么写?

梦叮咚

我想每天自动执行该shell,功能是:
1.每天检查/var/log/message,secure,mail等log文件.
2.挑出前一天的记录中包括"abcdef..."或"cdefab..."或"....."字样的行.
3.将这些内容发送到我的邮箱中.

如何做,我刚接触shell,请大家帮忙.

多谢了.

addwin

1. 写好这个shell:
2. 配在cronttab 中

rain0216

#!/bin/sh
$file="filename"
echo "" > $file
grep  "abcdef..."  /var/log/message >> $file
................
cat $file | mail name@domain -s"subject"
rm $file

梦叮咚

对我来说,难点是既包括abcd又包括cdef的选择.

比如:在今天(日期也要通过程序自动获得)的记录行里,出现"unaviabale"或者"error"的行.

rain0216

下面引用由梦叮咚在 2002/01/25 01:48pm 发表的内容：
对我来说,难点是既包括abcd又包括cdef的选择.
比如:在今天(日期也要通过程序自动获得)的记录行里,出现"unaviabale"或者"error"的行.

你的前一句是说和的关系，后面的例子是或者的关系，到底是哪一种啊

shirley

1. 写一个shell程序
#！/bin/sh
/usr/xpg4/bin/grep -E 'unaviabale|error' /var/adm/message > /tmp/file.$$
/usr/xpg4/bin/grep -E 'unaviabale|error' /var/adm/mail >> /tmp/file.$$
mailx -s &quot;....&quot; your-email-address@domain < /tmp/file.$$
rm /tmp/file.$$

2 将shell程序写入crontab

梦叮咚

[这个贴子最后由梦叮咚在 2002/01/28 01:34pm 编辑]

Jan 28 10:26:06 intranet sendmail[3359]: KAA03348: to=, delay=00:01:12, xdelay=00:00:00, mailer=local, stat=User unknown
Jan 28 10:26:06 intranet sendmail[3359]: KAA03348: KAA03359: DSN: User unknown
Jan 28 10:26:22 intranet sendmail[3364]: UAA20145: to=<5555555@goodforyou.com>, delay=3+13:37:35, xdelay=00:00:00, mailer=esmtp, relay=goodforyou.com. [212.100.230.160], stat=Deferred: Connection refused by goodforyou.com.
Jan 28 10:26:45 intranet sendmail[3359]: KAA03359: to=, delay=00:00:39, xdelay=00:00:39, mailer=esmtp, relay=public.ayptt.ha.cn. [202.102.230.147], stat=Sent (JAA27956 Message accepted for delivery)
Jan 28 10:26:57 intranet sendmail[3373]: KAA03373: from=, size=4795, class=0, pri=34795, nrcpts=1, msgid=<001001c1a79e$7cab5880$190aa8c0@linjing>, proto=ESMTP, relay=[192.168.10.25]
Jan 28 10:26:58 intranet sendmail[3375]: KAA03373: to=, delay=00:00:01, xdelay=00:00:01, mailer=esmtp, relay=ca-css.com. [211.157.248.24], stat=Sent (2.6.0 <001001c1a79e$7cab5880$190aa8c0@linjing> Queued mail for delivery)
Jan 28 10:28:25 intranet sendmail[3384]: KAA03384: from=, size=29486, class=0, pri=59486, nrcpts=1, msgid=<200201280157.KAA09511@member.medikorea.net>, bodytype=8BITMIME, proto=ESMTP, relay=member.medidas.co.kr [203.239.120.13]
Jan 28 10:28:25 intranet sendmail[3388]: KAA03384: to=, delay=00:00:09, xdelay=00:00:00, mailer=local, stat=Sent
Jan 28 10:31:32 intranet sendmail[3399]: KAA03399: ruleset=check_mail, arg1=, relay=member.medidas.co.kr [203.239.120.13], reject=451 ... Sender domain must resolve
Jan 28 10:31:32 intranet sendmail[3399]: KAA03399: from=, size=0, class=0, pri=0, nrcpts=0, proto=ESMTP, relay=member.medidas.co.kr [203.239.120.13]
以上是我的log文件，我想写个shell，自动查找当天记录中含有&quot;Sender domain must resolve&quot;或&quot;User unknown&quot;的行，并发邮件给我．大家看这样对不对．

today=&quot;Jan 28&quot;
/bin/grep $today &amp; &quot;Sender domain must resolve|User unknown&quot; /var/log/messages | mail me@domain.com

这样应该可以吧，但是变量today如何自动获到今天的日期并转为以上格式呢？

梦叮咚

不行呀，在命令行上运行
grep &quot;&quot;Sender domain must resolve|User unknown&quot; /var/log/messages
就出不来什么东西．怎么回事呢？

cpss

要加上参数-e 或者－E
例如：
/usr/xpg4/bin/grep -E &quot;Sender domain must resolve|User unknown&quot; /var/log/messages
或者
/usr/xpg4/bin/grep －e &quot;Sender domain must resove&quot; -e &quot;User unknown&quot; /var/log/messages

注意：是/usr/xpg4/bin/grep

feeling

[这个贴子最后由feeling在 2002/01/29 09:17pm 编辑]

2. #!/bin/sh
3. DD=`date |cut -c 5-10`
4. #捕获当前日期，只包括月、日（根据实际情况来确定）
5. for FF in /var/log/message /var/log/secure /var/log/mail
6.    do
7.         cat $FF |grep $DD |grep abcdef >> /home/yourpath/logfile
8.    done
9. # 分别cat几个日志文件，将里面含有特征字符的行重定向到/home/yourpath/logfile
10. mail yourmail /home/yourpath/logfile && rm /home/yourpath/logfile
11. # 向指定邮箱发送内容为/home/yourpath/logfile的邮件，成功后删除文件
12. # The End
13. # 未曾测试！

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