- 论坛徽章:
- 0
|
我要POST一段数据到APACHE去，
welcome.php是这样的：
<html><body>
<?php
echo "Upload： " . $_FILES["file"]["name"] . "<br />";
echo "Type: " . $_FILES["file"]["type"] . "<br />";
echo "Size: | . $_FILES["file"]["type"] . "<br />";
echo "Stored in : " . $_FILES["file"]["tmp_name"];
?>
</body></html>
然后我自己写了一个字符串发送POST请求的字符串
POST /welcome.php HTTP/1.1\r\n
Host: 127.0.0.1\r\n
Connection: keep-alive\r\n
User-Agent: Mozilla/5.0 (Windows; U; Windows NT 5.1; en-us) AppleWebKit/532/0 (KHTML, like Gecko) Chrome/3.0.195.33 Safari/532.0\r\n
Referer: http://127.0.0.1/index2.php\r\n
Conetent-Length: 192\r\n
Cache-Control: max-age=0\r\n
Origin: http://127.0.0.1\r\n
Content-Type: multipart/form-data; boundary=abcd\r\n
\r\n
--abcd\r\n
Content-Disposition: form-data; name="file"; filename="test.txt"\r\n
Content-Type: text/plain\r\n
\r\n
aaaaaaaaaa
\r\n--abcd--\r\n
但是APACHE的返回值总是这个
HTTP/1.1 200 OK
Date: Tue, 15 Dec 2009 13:31:27 GMT
Server: Apache/2.2.12 (Unix) PHP/5.3.0
X-Powered-By: PHP/5.3.0
Content-Length: 83
Keep-Alive: timeout=5, max=100
Connection: Keep-Alive
Content-Type: text/html
<html>
<body>
Upload: <br />Type: <br />Size: 0 Kb<br />Stored in: </body>
</html>
<!DOCTYPE HTML PUBLIC "-//IETF//DTD HTML 2.0//EN">
<html><head>
<title>501 Method Not Implemented</title>
</head><body>
<h1>Method Not Implemented</h1>
<p>--abcd to / not supported.<br />
</p>
</body></html>
APACHE返回200，但是似乎PHP处理这个文件的时候就出错了，这个是什么错误啊，谢谢指点 |
|
免费注册
发表于 2009-12-15 21:38
发表于 2009-12-16 00:10
