请问awk中如何同时以:和空格作为分隔符,空格可能是1个或2个或N个

lzolder

RT

squall1

-F"[ ]*|:"

lkk2003rty

-F "[ ]+"

lzolder

谢谢ls两位，通过测试用如下可以实现

1. awk -F ": | [ ]+"

复制代码

lzolder

晕倒，不行。
文件t如下

1. Enclosure Device ID: 8
   
2. Slot Number: 23
   
3. Device Id: 32
   
4. Sequence Number: 2
   
5. Media Error Count: 0
   
6. Other Error Count: 0
   
7. Predictive Failure Count: 0
   
8. Last Predictive Failure Event Seq Number: 0
   
9. PD Type: SATA
   
10. Raw Size: 931.512 GB [0x74706db0 Sectors]
    
11. Non Coerced Size: 931.012 GB [0x74606db0 Sectors]
    
12. Coerced Size: 930.390 GB [0x744c8000 Sectors]
    
13. Firmware state: Online
    
14. SAS Address(0): 0x500e004aaaaaaa17
    
15. Connected Port Number: 4(path0)
    
16. Inquiry Data:             9QJ3EBPVST31000340NS                            SN06
    
17. FDE Capable: Not Capable
    
18. FDE Enable: Disable
    
19. Secured: Unsecured
    
20. Locked: Unlocked
    
21. Foreign State: None
    
22. Device Speed: 3.0Gb/s
    
23. Link Speed: 3.0Gb/s
    
24. Media Type: Hard Disk Device
    

复制代码

执行

1. awk -F ": | [ ]+" '{print $2}' t

复制代码

后输出为：

1. 8
   
2. 23
   
3. 32
   
4. 2
   
5. 0
   
6. 0
   
7. 0
   
8. 0
   
9. SATA
   
10. 931.512 GB [0x74706db0 Sectors]
    
11. 931.012 GB [0x74606db0 Sectors]
    
12. 930.390 GB [0x744c8000 Sectors]
    
13. Online
    
14. 0x500e004aaaaaaa17
    
15. 4(path0)
    
16. 
    
17. Not Capable
    
18. Disable
    
19. Unsecured
    
20. Unlocked
    
21. None
    
22. 3.0Gb/s
    
23. 3.0Gb/s
    
24. Hard Disk Device
    

复制代码

看到那空白行了吧？不是我要的结果，我需要能打印9QJ3EBPVST31000340NS

where27

回复 5# lzolder


    -F':[ ]+'

beginner-bj

1. awk -F':[ ]+|[ ][ ]+' '{print $2}' t

复制代码

lzolder

ls两位均可，thanks

bbgg1983

好和谐

expert1

:[]+