[菜鸟求助]如何找到特定文本的下一行

dd

log文件aaa.txt的内容如下：
GZM01> lhsh 001200 db_info_license

100729-16:45:40 139.1.3.11 7.1y  stopfile=/tmp/6477
$ lhsh 001200 db_info_license

Software licensing data (Busy, Reqs, Rejs, Limit;
HARD[limit, alarm, timer, durat.]
SOFT[limit, alarm, timer, durat.]):
SCC:
B: 6498, Rq: 99269713, Rj: 0, L: 16842
H: [16837, ALARM_STATUS_OFF(0), ALARM_TIMER_NOT_RUNNING(0), 900]
S: [13469, ALARM_STATUS_OFF(0), ALARM_TIMER_NOT_RUNNING(0), 900]
AMR-WB:
B: 0, Rq: 0, Rj: 0, L: 0
H: [0, ALARM_STATUS_OFF(0), ALARM_TIMER_NOT_RUNNING(0), 900]
S: [0, ALARM_STATUS_OFF(0), ALARM_TIMER_NOT_RUNNING(0), 900]
G729:
B: 0, Rq: 0, Rj: 0, L: 0
H: [0, ALARM_STATUS_OFF(0), ALARM_TIMER_NOT_RUNNING(0), 900]
S: [0, ALARM_STATUS_OFF(0), ALARM_TIMER_NOT_RUNNING(0), 900]
VOIP:
B: 0, Rq: 0, Rj: 0, L: 0
H: [0, ALARM_STATUS_OFF(0), ALARM_TIMER_NOT_RUNNING(0), 900]
S: [0, ALARM_STATUS_OFF(0), ALARM_TIMER_NOT_RUNNING(0), 900]

swlMescCapacityCounters ...
MeSC  0: 787    MeSC  1: 810    MeSC  2: 818    MeSC  3: 817   
MeSC  4: 830    MeSC  5: 867    MeSC  6: 804    MeSC  7: 765   
MeSC  8: 0      MeSC  9: 0      MeSC 10: 0      MeSC 11: 0     
MeSC 12: 0      MeSC 13: 0      MeSC 14: 0      MeSC 15: 0     

$

GZM01> lhsh 001300 db_info_license

100729-16:45:55 139.1.3.11 7.1y  stopfile=/tmp/6477
$ lhsh 001300 db_info_license
lhsh: unknown command 'db_info_license'
$

GZM01> lhsh 000700 db_info_license

100729-16:46:14 139.1.3.11 7.1y  stopfile=/tmp/6477
$ lhsh 000700 db_info_license

Software licensing data (Busy, Reqs, Rejs, Limit;
HARD[limit, alarm, timer, durat.]
SOFT[limit, alarm, timer, durat.]):
SCC:
B: 0, Rq: 0, Rj: 0, L: 0xeeeeeeee (unlimited capacity)
H: [4008636137, ALARM_STATUS_OFF(0), ALARM_TIMER_NOT_RUNNING(0), 900]
S: [3206908909, ALARM_STATUS_OFF(0), ALARM_TIMER_NOT_RUNNING(0), 900]
........


我是想找到每个SCC的下一行，即：
B: 6498, Rq: 99269713, Rj: 0, L: 16842
B: 0, Rq: 0, Rj: 0, L: 0xeeeeeeee (unlimited capacity)

我在论坛里搜索过了，没找到特别类似的解。
先谢过各位了

kwokcn

grep -A 1 SCC URFILE
sed -n '/SCC/{n;p}' URFILE
awk '/SCC/{getline; print}' URFILE

expert1

grep -A 1
sed -n {n;p}'

kwokcn

1. 
   
2. awk 'ARGIND==1{a[$0]=1}ARGIND==2&&a[$0]{getline; print}' a b
   

复制代码

Shell_HAT

回复 4# frewise

1. while read line; do sed -n "/^$line$/{n;p}" file2; done < file1

复制代码

dd

太感谢了！

hantom

awk '/SCC/{a=NR+1}{if(a==NR) print$0 }'  aaa.log