刚学python，实验书上的2个小程序遇到的问题

wuqt

第一个：  if 语句，完全按照书上的书写

#!/usr/bin/python
# Filename: if.py

number = 23
guess = int(input('Enter an integer : '))

if guess == number:
    print('Congratulations, you guessed it.') # New block statrs here
        print('(but you do not win any prizes!)') # New block ends here
elif guess < number:
    print('No, it is a little higher than that') # Another block
        # You can do whatever you want in a block ...
else:
    print('No, it is a little lower than that')
        # You must have guess > number to reach here
print('Done')

执行后报错：

root@ubuntu:~$ python if
  File "if", line 9
    print('(but you do not win any prizes!)') # New block ends here
    ^
IndentationError: unexpected indent

第二个： while语句
#!/usr/bin/python
# Filename while.py

number == 23
running = Ture

while running:
    guess = int(input("Enter a integer: '))
       
        if guess == number:
            print('Congratulations, you guessed it.')
                running = False #thi cause the wile loop to stop
        elif guess < number:
            print('No, it is a little higher than that.')
else:
    print('The while loop is over.')
        # Do anything else you want to do here
print('Done')

执行后报错：
root@ubuntu:~$ python while
  File "while", line 8
    guess = int(input("Enter a integer: '))
                                          ^
SyntaxError: EOL while scanning string literal

请各位高人指点。 多谢！

OwnWaterloo

python缩进敏感， 所以

1. 
   
2. if guess == number:
   
3.     print('Congratulations, you guessed it.') # New block statrs here
   
4.         print('(but you do not win any prizes!)') # New block ends here
   

复制代码

改为：

1. 
   
2. if guess == number:
   
3.     print('Congratulations, you guessed it.') # New block statrs here
   
4.     print('(but you do not win any prizes!)') # New block ends here
   

复制代码

第2个： EOL(end of line) while scanning string literal
扫描string literal时遇见了行结束。

string literal的delimiter没有匹配：
int(input("Enter a integer: '))

starzhestarzhe

没看也楼上两个有啥区别

a515200

~~~~~~~~~~~~~~~

flying_away

input() 可以输入字符串

icykiss

第一个，二楼说对了，不过，第二个，可不只这个问题。看下面：

1. #!/usr/bin/python
   
2. # Filename while.py
   
3. 
   
4. number = 23
   
5. running = True
   
6. 
   
7. while running:
   
8.     guess = int(input("Enter a integer: "))
   
9.     if guess == number:
   
10.         print('Congratulations, you guessed it.')
    
11.         running = False #thi cause the wile loop to stop
    
12.     elif guess < number:
    
13.         print('No, it is a little higher than that.')
    
14. else:
    
15.     print('The while loop is over.')
    
16.         # Do anything else you want to do here
    
17. print('Done')

复制代码

icykiss

你的 number 不应该是 ＝＝ 23，running 是True，不是Ture，还有注意缩进和单双引号对应。

螺旋剑

我学习python的最大感触就是不要用tab键缩进哦，去python社区看下“八荣八耻”吧！！

wuqt

回复 2# OwnWaterloo


    感谢指点！明白啦！

wuqt

你的 number 不应该是 ＝＝ 23，running 是True，不是Ture，还有注意缩进和单双引号对应。
icykiss 发表于 2010-09-18 14:57

    非常感谢你的解答，我已经改正了缩进和拼写。现在遇到一个新的问题。

Traceback (most recent call last):
  File "while", line 4, in <module>
    number == 23
NameError: name 'number' is not defined


我要在number前定义number为什么类型吗？ 书上为什么没写呀？