急问,AIX下的date 怎么没有linux的date -d选项?

yuantong

现在有一脚本,在linux下,调试成功,在AIX上因为没有-d这个选项,死活不通过

#!/bin/bash
#传入合法日期或使用当前日期，并将其年和月的值取出
date=${1:-`date +%Y-%m-%d`}
year=$(date -d "$date" +%Y)
month=$(date -d "$date" +%m)
#day=$(date -d "$date" +%d)
#构造所求月的第一天，并求出为星期几
first_day="$year-$month-1"
number=$(date -d "$first_day" +%w )
#根据上面求出的星期几来构造出此月的第一个和第二个周六
if [ "$number" -eq 6 ]
then
        first_saturday="$first_day"
        second_saturday="$year-$month-$(( 1 + 7 ))"
        third_saturday="$year-$month-$(( 1 + 14 ))"
        fourth_saturday="$year-$month-$(( 1 + 21 ))"
        echo "This month's first Saturday is $first_saturday!"
        echo "This month's second saturday is $second_saturday!"
        echo "This month's third saturday is $third_saturday!"
        echo "This month's fourth saturday is $fourth_saturday!"
else
         first_saturday="$year-$month-$(( 6 - $number + 1 ))"
         second_saturday="$year-$month-$(( 6 - $number + 1 + 7 ))"
         third_saturday="$year-$month-$(( 6 - $number + 1 + 14 ))"
         fourth_saturday="$year-$month-$(( 6 - $number + 1 + 21 ))"
         echo "This month's first Saturday is $first_saturday!"
         echo "This month's second saturday is $second_saturday!"
         echo "This month's third saturday is $third_saturday!"
         echo "This month's third saturday is $fourth_saturday!"
fi

#如果当前日期等于第一个周六
if [ $(date -d "$first_saturday" +%Y%m%d) -eq $(date +%Y%m%d) ]then
         echo "execute the first task"
elif [ $(date -d "$second_saturday" +%Y%m%d) -eq $(date +%Y%m%d) ]then
         echo "execute the second task"
elif [ $(date -d "$third_saturday" +%Y%m%d) -eq $(date +%Y%m%d) ]then
        echo "execute the third task"
elif [ $(date -d "$fourth_saturday" +%Y%m%d) -eq $(date +%Y%m%d) ]then
        echo "execute the fourth task"
fi

如果AIX真没有这个选项,请问上面的脚本如何修改,谢谢

magnet2008

-d选项好像是gnu date的参数。