hearbeat 2.0中如何让2个资源不同时运行在同一个node上？

archangle

我的资源是以资源组的形式出现的。我用
<rsc_colocation id="production_testing_not_same" from="group_1"
                to="group_4" score="-INFINITY"/>;
的形式来限制，却不行？该如何做？

河里的鱼

- <cib admin_epoch="0" have_quorum="true" num_peers="2" origin="cluster1" cib_feature_revision="1" last_written="Tue Aug 23 18:00:40 2005" debug_source="finalize_join" ccm_transition="3" dc_uuid="1962eb25-a9bd-4522-a0ca-b4f746491145" generated="true" epoch="21" num_updates="356">;
- <configuration>;
- <crm_config>;
  <nvpair id="transition_idle_timeout" name="transition_idle_timeout" value="120s" />;
  <nvpair id="symmetric_cluster" name="symmetric_cluster" value="true" />;
  <nvpair id="no_quorum_policy" name="no_quorum_policy" value="freeze" />;
  </crm_config>;
- <nodes>;
  <node id="37f94cfb-d792-42b3-bcc9-287363a0ddb2" uname="cluster1" type="member" />;
  <node id="32937c79-4a6e-42bd-86c5-726e64336dde" uname="cluster2" type="member" />;
  <node id="1962eb25-a9bd-4522-a0ca-b4f746491145" uname="cluster3" type="member" />;
  </nodes>;
- <resources>;
- <group id="group_1">;
- <primitive class="heartbeat" id="IPaddr_1" provider="heartbeat" type="IPaddr">;
- <instance_attributes>;
- <attributes>;
  <nvpair name="1" value="192.168.10.3" />;
  </attributes>;
  </instance_attributes>;
  </primitive>;
  <primitive class="lsb" id="httpd_2" provider="heartbeat" type="httpd" />;
  </group>;
- <group id="group_4">;
- <primitive class="heartbeat" id="IPaddr_4" provider="heartbeat" type="IPaddr">;
- <instance_attributes>;
- <attributes>;
  <nvpair name="1" value="192.168.10.5" />;
  </attributes>;
  </instance_attributes>;
  </primitive>;
  <primitive class="lsb" id="httpd_5" provider="heartbeat" type="httpd" />;
  </group>;
  </resources>;
- <constraints>;
- <rsc_location id="rsc_location_group_1" rsc="group_1">;
- <rule id="prefered_location_group_1" score="100">;
  <expression attribute="#uname" operation="eq" value="cluster1" />;
  </rule>;
- <rule id="prefered_location_group_2" score="50">;
  <expression attribute="#uname" operation="eq" value="cluster3" />;
  </rule>;
- <rule id="prefered_location_group_3" score="-INFINITY">;
  <expression attribute="#uname" operation="eq" value="cluster2" />;
  </rule>;
  </rsc_location>;
- <rsc_location id="rsc_location_group_4" rsc="group_4">;
- <rule id="prefered_location_group_4" score="100">;
  <expression attribute="#uname" operation="eq" value="cluster2" />;
  </rule>;
- <rule id="prefered_location_group_5" score="50">;
  <expression attribute="#uname" operation="eq" value="cluster3" />;
  </rule>;
- <rule id="prefered_location_group_6" score="-INFINITY">;
  <expression attribute="#uname" operation="eq" value="cluster1" />;
  </rule>;
  </rsc_location>;
  </constraints>;
  </configuration>;
  <status />;
  </cib>;


这个也许对你有用

archangle

节点太多好象不太适用了。

河里的鱼

[quote]原帖由 "archangle"]节点太多好象不太适用了。[/quote 发表：


存在这个问题,不过好像多节点支持不是太理想

archangle

官方说支持16个节点。还有写高级规则他们的站点上还没写出来，看起来是太忙了。我看他们的计划安排中说会做图形的管理界面。

河里的鱼

我打听过,好像IBM也做,和他们约好了,明天做这个多节点的

archangle

那他们得收多少钱啊。

河里的鱼

好像8收钱

archangle

免费上门来做还不收钱？

河里的鱼

[quote]原帖由 "archangle"]免费上门来做还不收钱？[/quote 发表：


当然了,只要买IBM的东西