求 shell 流量数值差脚本编写！

464735790

怎么把shell脚本第一次执行的数值和第二次执行的数值做差值比较啊？

snmpwalk -v 2c -c snmppwv2 10.242.193.126 1.3.6.1.2.1.2.2.1.10

IF-MIB::ifInOctets.1 = Counter32: 12431219
IF-MIB::ifInOctets.65539 = Counter32: 1380100376  eth0
IF-MIB::ifInOctets.65540 = Counter32: 1891518233  eth1



snmpwalk -v 2c -c snmppwv2 10.242.193.126 1.3.6.1.2.1.2.2.1.16
IF-MIB::ifOutOctets.1 = Counter32: 12431219
IF-MIB::ifOutOctets.65539 = Counter32: 4276940831  eth0
IF-MIB::ifOutOctets.65540 = Counter32: 1462738033  eth1

in和out 的值，eth0和eth1    1分钟和5分钟的差值，怎么算啊？

nakalzz

1. set InValue = `grep ifInOctets.65539 urfile | sed -e "s/.*Counter32: \(.*\)eth0/\1/g" `
   
2. set OutValue = `grep ifOutOctets.65539 urfile | sed -e "s/.*Counter32: \(.*\)eth0/\1/g"`
   
3. 
   
4. InValue - OutValue is what you want

复制代码

winway1988

参考一下

1. in1=$(snmpwalk -v 2c -c snmppwv2 10.242.193.126 1.3.6.1.2.1.2.2.1.10 | awk '/eth0$/{print $(NF-1)}')
   
2. in2=$(snmpwalk -v 2c -c snmppwv2 10.242.193.126 1.3.6.1.2.1.2.2.1.16 | awk '/eth0$/{print $(NF-1)}')
   
3. echo $((in2 - in1))

复制代码

nakalzz

回复 3# winway1988


恩 NF的用法 学习了 谢谢