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问题一、我创建了目录/kernel,然后我用uname -r看了我当前的内核信息.
之后我把内核文件/boot/vmlinuz-2.6.32-220.el6.i686以及initramfs-2.6.32-220.el6.i686.img
复制粘贴到目录/kernel里。
然后我备份了/boot/grub/grub.conf然后改名为/boot/grub/grub.conf.prelab4.2
问题:如何引导新的内核即我复制的原内核、
在内核信息里添加参数panic=42(什么意思这个命令)
把引导程序的密码设为(redhat)
保存修改内核配置文件
下面是我的内核配置文件
# grub.conf generated by anaconda
#
# Note that you do not have to rerun grub after making changes to this file
# NOTICE: You do not have a /boot partition. This means that
# all kernel and initrd paths are relative to /, eg.
# root (hd0,0)
# kernel /boot/vmlinuz-version ro root=/dev/sda1
# initrd /boot/initrd-[generic-]version.img
#boot=/dev/sda
default=0
timeout=5
splashimage=(hd0,0)/boot/grub/splash.xpm.gz
hiddenmenu
title Red Hat Enterprise Linux (2.6.32-220.el6.i686)
root (hd0,0)
kernel /boot/vmlinuz-2.6.32-220.el6.i686 ro root=UUID=810a45e3-5294-4139-b2c6-52da3e4a433e rd_NO_LUKS KEYBOARDTYPE=pc KEYTABLE=us rd_NO_MD quiet rhgb crashkernel=auto LANG=zh_CN.UTF-8 rd_NO_LVM rd_NO_DM
initrd /boot/initramfs-2.6.32-220.el6.i686.img
额、我是新手 、根据书上学可是这点不懂额
轻拍额、
谢了
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