64位 位运算的问题 请教各位

senic

是想做个用8个字节的unsigned long 存8个小于255的无符整数的小函数工具
在移位的时候 发现和预期不一样  超过32位的移不上去  
请教各位  是我代码的问题  还是移位操作只能32位范围内

系统是64位的centos

1. #include <stdio.h>
   
2. 
   
3. unsigned long SetByteToLong(unsigned long i, unsigned char c, int pos)
   
4. {
   
5.         printf("i=%d (%.16x),c=%d,pos=%d\n", i , i, c ,pos);
   
6.         unsigned long tmpl = -1;
   
7.         printf("%.16x\n", tmpl);
   
8.         unsigned long llll = ((unsigned long)c) << (8*(pos-1));
   
9.         printf("%.16x\n", llll);
   
10.         tmpl = tmpl & llll;
    
11.         printf("%.16x\n", tmpl);
    
12.         i = tmpl | i;
    
13.         printf("%.16x, %.16x\n", i, i << 8);
    
14. 
    
15.         return i;
    
16. }
    
17. 
    
18. 
    
19. int main()
    
20. {
    
21.         unsigned int aaa = 8;
    
22.         unsigned long bbb = 0;
    
23. 
    
24.         printf ("start:%d sizeof(unsigned long) =%d\n", aaa, sizeof(unsigned long));
    
25.         bbb = SetByteToLong(bbb, (unsigned char)aaa, 1);
    
26.         bbb = SetByteToLong(bbb, (unsigned char)aaa, 2);
    
27.         bbb = SetByteToLong(bbb, (unsigned char)aaa, 3);
    
28.         bbb = SetByteToLong(bbb, (unsigned char)aaa, 4);
    
29.         bbb = SetByteToLong(bbb, (unsigned char)aaa, 5);
    
30.         bbb = SetByteToLong(bbb, (unsigned char)aaa, 6);
    
31.         bbb = SetByteToLong(bbb, (unsigned char)aaa, 7);
    
32.         bbb = SetByteToLong(bbb, (unsigned char)aaa, 8);
    
33.         printf ("end:%x \n", bbb);
    
34. 
    
35.         return 0;
    
36. }

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执行结果

1. start:8 sizeof(unsigned long) =8
   
2. i=0 (0000000000000000),c=8,pos=1
   
3. 00000000ffffffff
   
4. 0000000000000008
   
5. 0000000000000008
   
6. 0000000000000008, 0000000000000800
   
7. i=8 (0000000000000008),c=8,pos=2
   
8. 00000000ffffffff
   
9. 0000000000000800
   
10. 0000000000000800
    
11. 0000000000000808, 0000000000080800
    
12. i=2056 (0000000000000808),c=8,pos=3
    
13. 00000000ffffffff
    
14. 0000000000080000
    
15. 0000000000080000
    
16. 0000000000080808, 0000000008080800
    
17. i=526344 (0000000000080808),c=8,pos=4
    
18. 00000000ffffffff
    
19. 0000000008000000
    
20. 0000000008000000
    
21. 0000000008080808, 0000000008080800
    
22. i=134744072 (0000000008080808),c=8,pos=5
    
23. 00000000ffffffff
    
24. 0000000000000000
    
25. 0000000000000000
    
26. 0000000008080808, 0000000008080800
    
27. i=134744072 (0000000008080808),c=8,pos=6
    
28. 00000000ffffffff
    
29. 0000000000000000
    
30. 0000000000000000
    
31. 0000000008080808, 0000000008080800
    
32. i=134744072 (0000000008080808),c=8,pos=7
    
33. 00000000ffffffff
    
34. 0000000000000000
    
35. 0000000000000000
    
36. 0000000008080808, 0000000008080800
    
37. i=134744072 (0000000008080808),c=8,pos=8
    
38. 00000000ffffffff
    
39. 0000000000000000
    
40. 0000000000000000
    
41. 0000000008080808, 0000000008080800
    
42. end:8080808

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hellioncu

printf的格式问题，%x应改为 %lx，或者%llx

senic

   谢谢兄台

1. start:8 sizeof(unsigned long) =8
   
2. i=0 (0000000000000000),c=8,pos=1
   
3. ffffffffffffffff
   
4. 0000000000000008
   
5. 0000000000000008
   
6. 0000000000000008, 0000000000000800
   
7. i=8 (0000000000000008),c=8,pos=2
   
8. ffffffffffffffff
   
9. 0000000000000800
   
10. 0000000000000800
    
11. 0000000000000808, 0000000000080800
    
12. i=2056 (0000000000000808),c=8,pos=3
    
13. ffffffffffffffff
    
14. 0000000000080000
    
15. 0000000000080000
    
16. 0000000000080808, 0000000008080800
    
17. i=526344 (0000000000080808),c=8,pos=4
    
18. ffffffffffffffff
    
19. 0000000008000000
    
20. 0000000008000000
    
21. 0000000008080808, 0000000808080800
    
22. i=134744072 (0000000008080808),c=8,pos=5
    
23. ffffffffffffffff
    
24. 0000000800000000
    
25. 0000000800000000
    
26. 0000000808080808, 0000080808080800
    
27. i=134744072 (0000000808080808),c=8,pos=6
    
28. ffffffffffffffff
    
29. 0000080000000000
    
30. 0000080000000000
    
31. 0000080808080808, 0008080808080800
    
32. i=134744072 (0000080808080808),c=8,pos=7
    
33. ffffffffffffffff
    
34. 0008000000000000
    
35. 0008000000000000
    
36. 0008080808080808, 0808080808080800
    
37. i=134744072 (0008080808080808),c=8,pos=8
    
38. ffffffffffffffff
    
39. 0800000000000000
    
40. 0800000000000000
    
41. 0808080808080808, 0808080808080800
    
42. end:0808080808080808

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