- 论坛徽章:
- 0
|
本帖最后由 itbigirl 于 2013-06-16 13:46 编辑
gdfg hgfh jhgj jhg jhgj
以上是excl格式。
功能:读取数据,插入数据库(包括空数据)。
问题:读取不了空数据。
代码:- private static List<List<Object>> read2007Excel(File file)
- throws IOException {
- List<List<Object>> list = new LinkedList<List<Object>>();
- // 构造 XSSFWorkbook 对象,strPath 传入文件路径
- XSSFWorkbook xwb = new XSSFWorkbook(new FileInputStream(file));
- // 读取第一张表格内容
- XSSFSheet sheet = xwb.getSheetAt(0);
- Object value = null;
- XSSFRow row = null;
- XSSFCell cell = null;
- for (int i = (sheet.getFirstRowNum()+1); i <=(sheet.getPhysicalNumberOfRows()-1); i++) {
- row = sheet.getRow(i);
- if (row == null) {
- continue;
- }
- List<Object> linked = new LinkedList<Object>();
- for (int j = row.getFirstCellNum(); j <= row.getLastCellNum(); j++) {
- cell = row.getCell(j);
- if (cell == null) {
- continue;
- }
- DecimalFormat df = new DecimalFormat("0");// 格式化 number String字符
- SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd");// 格式化日期字符串
- DecimalFormat nf = new DecimalFormat("0");// 格式化数字
- switch (cell.getCellType()) {
- case XSSFCell.CELL_TYPE_STRING:
- System.out.println(i + "行" + j + " 列 is String type");
- value = cell.getStringCellValue();
- break;
- case XSSFCell.CELL_TYPE_NUMERIC:
- System.out.println(i + "行" + j
- + " 列 is Number type ; DateFormt:"
- + cell.getCellStyle().getDataFormatString());
- if ("@".equals(cell.getCellStyle().getDataFormatString())) {
- value = df.format(cell.getNumericCellValue());
- } else if ("General".equals(cell.getCellStyle()
- .getDataFormatString())) {
- value = nf.format(cell.getNumericCellValue());
- } else {
- value = sdf.format(HSSFDateUtil.getJavaDate(cell
- .getNumericCellValue()));
- }
- break;
- case XSSFCell.CELL_TYPE_BOOLEAN:
- System.out.println(i + "行" + j + " 列 is Boolean type");
- value = cell.getBooleanCellValue();
- break;
- case XSSFCell.CELL_TYPE_BLANK:
- System.out.println(i + "行" + j + " 列 is Blank type");
- value = "";
- break;
- default:
- System.out.println(i + "行" + j + " 列 is default type");
- value = cell.toString();
- }
- linked.add(value);
- }
- list.add(linked);
- }
- return list;
- }
复制代码 测试结果:
1行0 列 is String type
1行2 列 is String type
1行4 列 is String type
1行5 列 is String type
1行11 列 is String type
[[gdfg, hgfh, jhgj, jhg, jhgj]]
希望有人帮助解答,感谢。 |
|