这是什么情况，谁来解释一下

hailongchang

1. use v5.10;
   
2. use warnings;
   
3. use strict;
   
4. 
   
5. 
   
6. my @list = qw(1 2 3 4 5);
   
7. 
   
8. my @rlist = reverse @list;
   
9. 
   
10. say scalar @list;
    
11. say scalar @rlist;
    
12. 
    
13. say (scalar (reverse @list));
    

复制代码

expected:
5
5
5
got:
5
5
54321

最后一条语句应该打印的也是5，为什么会是54321， scalar标记符不是将上下文环境转换为scalar了吗，为什么还会打印54321？

hailongchang

不好意思， 这个问题有点想当然了，刚刚perldoc了一下，看到这么一段

reverse LIST
In list context, returns a list value consisting of the elements of LIST in the opposite order. In scalar context, concatenates the elements of LIST and returns a string value with all characters in the opposite order.

瞬间明白了！