（求助）使用shell命令按标识分割文件

Pugna_zfr

一个文件内容如下：
Service "syncdb" has 1 instance(s).
  Instance "syncdb", status READY, has 1 handler(s) for this service...
Service "syncdbXDB" has 2 instance(s).
  Instance "syncdb1", status READY, has 1 handler(s) for this service...
  Instance "syncdb2", status READY, has 1 handler(s) for this service...
Service "syncdb_XPT" has 1 instance(s).
  Instance "syncdb", status READY, has 1 handler(s) for this service...



使用什么shell命令可以将上面的文件分割为以下3个文件：

第一个文件：
Service "syncdb" has 1 instance(s).
  Instance "syncdb", status READY, has 1 handler(s) for this service...
第二个文件：
Service "syncdbXDB" has 2 instance(s).
  Instance "syncdb1", status READY, has 1 handler(s) for this service...
  Instance "syncdb2", status READY, has 1 handler(s) for this service...
第三个文件：
Service "syncdb_XPT" has 1 instance(s).
  Instance "syncdb", status READY, has 1 handler(s) for this service...

也就是按Service开头为分割标识，相邻的两个Service之间的行数是不确定的，可能是1行，也可能是n行。

谢谢！

polyahu

1. awk '{if($1 == "Service" && $2 == "\"syncdb\""){n=$4+1;}else{;};if(n>0){print $0;n=n-1}}' data.txt > output
   
2. awk '{if($1 == "Service" && $2 == "\"syncdbXDB\""){n=$4+1;}else{;};if(n>0){print $0;n=n-1}}' data.txt > output.XDB
   
3. awk '{if($1 == "Service" && $2 == "\"syncdb_XPT\""){n=$4+1;}else{;};if(n>0){print $0;n=n-1}}' data.txt > output._XPT

复制代码

仅供参考。

laliheyi

回复 1# Pugna_zfr


    awk '/^Service/{file=$2;gsub(/\"/,"",file)}{print $0 > file}' service.txt

Pugna_zfr

回复 2# polyahu


    谢谢！
    我用 awk '{if($1 == "Service" && $2 !~/XDB/ && $2 !~/_XPT/ && $2 !~/PLSExtProc/){n=$4+1;}else{;};if(n>0){print $0;n=n-1}}' inputfile 基本达到要求了，就是有个点遗憾，不能自动按Service名称分割。不过还是很不错了！3Q

Pugna_zfr

回复 3# laliheyi


    试了下，好像有点问题。
    -bash-3.2$ lsnrctl status | awk '/^Service/{file=$2;gsub(/\"/,"",file)}{print $0 > file}'
    awk: (FILENAME=- FNR=1) fatal: expression for `>' redirection has null string value

    -bash-3.2$ awk --version
    GNU Awk 3.1.5

Pugna_zfr

回复 4# Pugna_zfr


    哦，不好意思，我刚才搞错了。我把lsnrctl status的输出内容格式化成1L中的那样是正常的。
    谢谢！ :wink:

laliheyi

回复 5# Pugna_zfr


   {:2_166:}  lsnrctl status 结果前面那部分结果你的需求中没有给出。如果那部分不需要可以如此
awk '/^Service/{file=$2;gsub(/\"/,"",file)}file!=""{print $0 > file}'

WilliBhamlll

回复 1# Pugna_zfr

1. $awk '/^Service/{++i}{print >"file"i}' file
   
2. 
   
3. $cat file
   
4. Service "syncdb" has 1 instance(s).
   
5.   Instance "syncdb", status READY, has 1 handler(s) for this service...
   
6. Service "syncdbXDB" has 2 instance(s).
   
7.   Instance "syncdb1", status READY, has 1 handler(s) for this service...
   
8.   Instance "syncdb2", status READY, has 1 handler(s) for this service...
   
9. Service "syncdb_XPT" has 1 instance(s).
   
10.   Instance "syncdb", status READY, has 1 handler(s) for this service...
    
11. 
    
12. $cat file1
    
13. Service "syncdb" has 1 instance(s).
    
14.   Instance "syncdb", status READY, has 1 handler(s) for this service...
    
15. $cat file2
    
16. Service "syncdbXDB" has 2 instance(s).
    
17.   Instance "syncdb1", status READY, has 1 handler(s) for this service...
    
18.   Instance "syncdb2", status READY, has 1 handler(s) for this service...
    
19. $cat file3
    
20. Service "syncdb_XPT" has 1 instance(s).
    
21.   Instance "syncdb", status READY, has 1 handler(s) for this service...

复制代码

Pugna_zfr

回复 7# laliheyi


    嗯。

命令中的 print $0 > file 看不太明白。file是前面的service名称，$0是匹配到以Service开头的每一行吗？
我改了下这个命令，感觉$0是把每一行都匹配了，不管是否以Service开头。但是，如果$0是每一行的话，直接用 > 到文件，居然没有把原文件的内容（即刚刚输出到文件的上一行内容）覆盖？？？
a.txt中是格式化好的文本内容。

-bash-3.2$ awk '/^Service/{file=$2;gsub(/\"/,"",file)}{print "test line\n"$0}' a.txt
test line
Service "PLSExtProc" has 1 instance(s).
test line
  Instance "PLSExtProc", status UNKNOWN, has 1 handler(s) for this service...
test line
Service "syncdb" has 1 instance(s).
test line
  Instance "syncdb", status READY, has 1 handler(s) for this service...
test line
Service "syncdbXDB" has 1 instance(s).
test line
  Instance "syncdb", status READY, has 1 handler(s) for this service...
test line
Service "syncdb_XPT" has 1 instance(s).
test line
  Instance "syncdb", status READY, has 1 handler(s) for this service...

Pugna_zfr

回复 8# WilliBhamlll


    这个 awk '/^Service/{++i}{print >"file"i}' file 是不是匹配以Service开头的内容，如果匹配到就执行{++i}{print >"file"i} ，直到遇到下一个匹配Service开头的行，再执行{++i}{print >"file"i} ，然后一直这么循环下去，直到读取完文件的内容 ？？