awk文件每一行所有列数据求和

jason680

回复 10# pdzcowboy

print %s, sum/NF
chang to
printf("%s %f\n",$0,sum/NF)
   

Herowinter

回复 10# pdzcowboy

改成这样

1. cat myfile|awk '{for(i=1;i<=NF;i++)sum+=$i;printf "%s\t%f\n",$0,sum/NF;sum=0}'
   
2. 162616.534758647 136543.71100776 112965.741246305         137375.329004
   
3. 85181.9193508478 204094.759382577 171434.344233055         153570.340989
   
4. 128583.994276291 141911.700271563 126981.817796069         132492.504115
   
5. 171259.827021216 206842.518859144 188080.600873984         188727.648918
   
6. 
   

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yaozhibing41001

回复 10# pdzcowboy

1. # awk '{for(i=1;i<=NF;i++)sum+=$i;printf "%s  %.2f\n",$0,sum/NF;sum=0}'  file

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yestreenstars

回复 10# pdzcowboy

1. awk '{for(i=0;i++<NF;)s+=$i;printf "%s %f\n",$0,s/NF;s=0}'

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elu_ligao

awk '{for(i=1;i<=NF;++i)a[NR]+=$i;printf "%s\t%f\n",$0,a[NR]/NF}'

kernel69

perl的

1. $ cat 11
   
2. 1 2 3 4 5
   
3. 1 2 3 4 5
   
4. 1 2 3 4 5
   
5. 1 2 3 4 5
   
6. 1 2 3 4 5
   
7. $ perl -MList::Util=sum -lane 'print "@F ".sum @F' 11
   
8. 1 2 3 4 5 15
   
9. 1 2 3 4 5 15
   
10. 1 2 3 4 5 15
    
11. 1 2 3 4 5 15
    
12. 1 2 3 4 5 15
    
13. $

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回复 1# pdzcowboy


   

rulebook

awk '{s="";for(i=1;i<=NF;i++){s=s+$i};print $0,s}' o