case 语句执行报错syntax error near unexpected token

lingfengjian

新人学习shell，写了一个创建指定目录，并将某个目录下的指定文件拷贝到该目录下的脚本，不过运行时出现如下错误
copy_file.sh: line 20: syntax error near unexpected token `$is_postive'
copy_file.sh: line 20: `     case $is_postive in'
这第20行这个变量is_postive到底哪儿有问题，各位大神帮忙看下哈

#!/bin/sh

input_num(){
if [ $# -ne 1 ]
then
echo "arguments error"
fi

num=""

while :
do
read _num
is_postive=`echo ${_num}|sed 's/[0-9]//g'|awk '{print length($0)}'`
if [ $_num -ne 0 ]
then
     case "$is_postive" in
     1)
       echo "your input is not a positive integer,please input a positive integer";num="";;
     case "$is_postive" in
     0)
       num=${_num};break;;
     *)
       echo "unknown error,please input a positive integer again";num="";;
     esac
else
echo "your input number is zero,please input a positive integer"
fi
done

export num
return 0
}

input_num "please input the counts of dictionaries you want to create and copy"

if [ -d $HOME/aa ]
then
rm -rf $HOME/aa
fi

count="0"
while [ $count -lt $num ]
do
   count =`echo $((count + 1))`
   mkdir -p $HOME/aa/bb/ch${count} > /dev/null 2>&1
   if [ $? -ne 0 ]
     then echo "create dictionary ch${count} failed,please check it";continue
   fi
   
   for i in chm doc xls html
   do
     if [ -f $HOME/*.${i} ] && [ -d $HOME/aa/bb/ch${count} ]
         then
           cp $HOME/*.${i} $HOME/aa/bb/ch${count} > dev/null 2>&1
           if [ $? -ne 0 ]
           then
             echo "copy $HOME/*.${i} to $HOME/aa/bb/ch${count} failed"
           else
             echo "copy ${i} to ch${count} successful"
           fi
         elif [ ! -f $HOME/*.${i} ]
     then
            echo "the ${i} files are not exit"
         elif [ ! -d $HOME/aa/bb/ch${count} ]
     then
        echo "$HOME/aa/bb/ch${count} is not exit"
     else
           echo "unkown error"
         fi
   done
done

runintostar

感觉是
0)上面那行多了个case

lingfengjian

的确是这个问题，语法没过关啊 多谢了回复 2# runintostar