while do ... done的嵌套结构中，第一个while和do之间必须要加一个空行吗？

我是个野鸭子

现有如下程序：

1. #!/bin/sh
   
2. 
   
3. #set -x
   
4. 
   
5. CACHE_PATH=/var/lib/HPCCSystems/mydropzone/cache/
   
6. VERINT_PATH=/var/lib/HPCCSystems/mydropzone/verint/
   
7. ESOON_PATH=/var/lib/HPCCSystems/mydropzone/esoon/
   
8. HP_PATH=/var/lib/HPCCSystems/mydropzone/hp/
   
9. 
   
10. ANS=yes
    
11. ANS2=yes
    
12. KWANS=yes
    
13. KEYWORD=""
    
14. CMD=""
    
15. 
    
16. while [ "$ANS" = "yes" -o "$ANS" = "y" -o "$ANS" = "Y" ]
    
17. 
    
18. do
    
19.   echo "Enter a folder name(cache[c], verint[v], esoon[e], hp[h]):"
    
20.   read NAME
    
21.   echo "Enter the key word:"
    
22.   read WORD
    
23.   echo "Do you need to input more key words? yes[y/Y] or no[n/N]"
    
24.   read KWANS
    
25.   while [ "$KWANS" = "yes" -o "$KWANS" = "y" -o "$KWANS" = "Y" ]
    
26.   do
    
27.     KEYWORD=$KEYWORD" grep "$WORD" | "
    
28.     echo "Enter the key word:"
    
29.     read WORD
    
30.     echo "Do you need to input more key words? yes[y/Y] or no[n/N]"
    
31.     read KWANS
    
32.   done
    
33.   CMD="find "$CACHE_PATH" -name \"*.*\" | xargs"$KEYWORD"more"
    
34.   echo $CMD
    
35. 
    
36. 
    
37.   echo "Continue? Enter yes[y/Y] or no[n/N]"
    
38.   read ANS
    
39.   echo ""
    
40. done
    

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注意第一个while和do之间，有个空行

我如果把这个空行删除了，变成如下的代码：

1. #!/bin/sh
   
2. 
   
3. #set -x
   
4. 
   
5. CACHE_PATH=/var/lib/HPCCSystems/mydropzone/cache/
   
6. VERINT_PATH=/var/lib/HPCCSystems/mydropzone/verint/
   
7. ESOON_PATH=/var/lib/HPCCSystems/mydropzone/esoon/
   
8. HP_PATH=/var/lib/HPCCSystems/mydropzone/hp/
   
9. 
   
10. ANS=yes
    
11. ANS2=yes
    
12. KWANS=yes
    
13. KEYWORD=""
    
14. CMD=""
    
15. 
    
16. while [ "$ANS" = "yes" -o "$ANS" = "y" -o "$ANS" = "Y" ]
    
17. do
    
18.   echo "Enter a folder name(cache[c], verint[v], esoon[e], hp[h]):"
    
19.   read NAME
    
20.   echo "Enter the key word:"
    
21.   read WORD
    
22.   echo "Do you need to input more key words? yes[y/Y] or no[n/N]"
    
23.   read KWANS
    
24.   while [ "$KWANS" = "yes" -o "$KWANS" = "y" -o "$KWANS" = "Y" ]
    
25.   do
    
26.     KEYWORD=$KEYWORD" grep "$WORD" | "
    
27.     echo "Enter the key word:"
    
28.     read WORD
    
29.     echo "Do you need to input more key words? yes[y/Y] or no[n/N]"
    
30.     read KWANS
    
31.   done
    
32.   CMD="find "$CACHE_PATH" -name \"*.*\" | xargs"$KEYWORD"more"
    
33.   echo $CMD
    
34. 
    
35. 
    
36.   echo "Continue? Enter yes[y/Y] or no[n/N]"
    
37.   read ANS
    
38.   echo ""
    
39. done
    

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就会报错：
./test.sh: line 38: syntax error near unexpected token `done'
./test.sh: line 38: `done '
意思是最后一行的done没认出来

请问while中套while，为什么第一个while和do之间必须加入一个空行呢？

liion631818

没有问题啊。有什么特殊字符吗

bulletmarquis

回复 1# 我是个野鸭子


    没听过这说法。。。莫非LZ的换行符有问题？试试dos2unix再执行呢

Shell_HAT

如果你的文件是从Windows里面复制到Linux里面的，需要先转换一下格式：

1. dos2unix test.sh

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