求shell mac地址

睿智2012

cat /etc/udev/rules.d/70-persistent-net.rules
# This file was automatically generated by the /lib/udev/write_net_rules
# program, run by the persistent-net-generator.rules rules file.
#
# You can modify it, as long as you keep each rule on a single
# line, and change only the value of the NAME= key.

# PCI device 0x8086:0x100f (e1000)
SUBSYSTEM=="net", ACTION=="add", DRIVERS=="?*", ATTR{address}=="00:0c:29:21:b1:49", ATTR{type}=="1", KERNEL=="eth*", NAME="eth0"

想要得到00:0c:29:21:b1:49这个mac的shell！

搞了半天没搞出来

谢谢

reyleon

1. grep -Po '(?<=ATTR{address}==")[^"]+' /etc/udev/rules.d/70-persistent-net.rules

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qq58945591

回复 1# 睿智2012


    awk -F\" '{print $8}' /etc/udev/rules.d/70-persistent-net.rules

睿智2012

reyleon 发表于 2015-03-21 13:56

谢谢两位了！ 中间的正则不理解啊

回复 3# qq58945591


出现很多的空行啊！

我是一隻羊

1. grep -Eo '([0-9a-e]{2}[:]?){6}' inputfile

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1. sed -nr '/ATTR/s/.*\{address\}=="([^"]+).*/\1/p' inputfile

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1. sed -r ':1;/ATTR/!{N;D};s/.*\{address\}=="([^"]+).*/\1/;t2;b1;:2;q' inputfile

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1. awk -F\" '/ATTR/{print $8}' inputfile

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1. awk -vRS='ATTR{address}=="' 'NR>1{sub(/\".*/,"",$0);print}' inputfile

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o枫叶o飘零

1. 
   
2. grep -Po '(\w+:){5}(\w+)'
   
3. 
   
4. awk -F\" '/address/{print $8}'

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睿智2012

学习了，谢谢！

qq5910225

o枫叶o飘零 发表于 2015-03-21 16:19

echo '00:50:56:9e:40:00dfsdf'|grep -Po '(\w+{5}(\w+)'

echo '00:50:56:9e:40:00dfsdf'|grep -oP '\w{2}(:\w{2}){5}'

o枫叶o飘零

回复 8# qq5910225


    ?

drakness

1. grep ATTR /etc/udev/rules.d/70-persistent-net.rules  |  awk -F'(,|\")'  '{print $11}'
   
2. grep ATTR  /etc/udev/rules.d/70-persistent-net.rules | awk -F, '{a=gensub("ATTR{address}==","","g",$4);print gensub("\"","","g",a)}'
   
3. 
   

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