请教如何交换两行

jason680

回复 1# zsjan

$ awk -vs=3 -ve=5 '
NR<s { print}
NR==s{sv=$0}
s<NR&&NR<e{kp=kp$0"\n"}
NR==e{print $0"\n"kp sv}
e<NR{print}
' FILE
1 a
2 b
5 e
4 d
3 c
6 f
7 g

   

MMMIX

回复 1# zsjan


    把文本读入数组，然后想怎么交换怎么交换，完了之后再输出就是了。

聆雨淋夜

awk '{a[NR]=$0}END{n=a[3];a[3]=a[5];a[5]=n;for(i=1;i<=NR;i++)print a[i]}' file

fh21_xuejinlian

awk '{a[$1]=$2}END{t=a[3];a[3]=a[5];a[5]=t;for(i=1;i<=asorti(a,b);i++)print i, a[b[i]]}'  file

StarWingsss

我就写了一下，有点多

#! /bin/bash

echo -e "exchange ramdom line"
read -p "input line_number 1:" l1
read -p "input line_number 2:" l2
read -p "input file absolty path:" path

awk '{print NR,$0}' $path > path.bak

t1=$(awk -v line=$l1 '{if(NR==line) print $2}' path.bak)
t2=$(awk -v line=$l2 '{if(NR==line) print $2}' path.bak)

awk -v line=$l1 -v tmp=$t2 '{if(NR==line) $2=tmp} {print $0}' path.bak > path.bak1
awk -v line=$l2 -v tmp=$t1 '{if(NR==line) $2=tmp} {print $2}' path.bak1 > path.bak2

echo -e "Final resualt is:"
awk '1' path.bak2

read -n1 -t5 -p "Do you want to save the result[Y/N]?" answer
echo ""
case $answer in
Y|y)
   read -p "input the absoluty path to save: " path1
   echo "your path is $path1"
   cp path.bak2 $path1
   ;;
N|n)
   echo "shell is to exit"
   ;;
*)
   echo "input error"
  ;;
esac

rm -f path.bak*
exit 0

moperyblue

1. sed -r '3{:a;N;5!ba;s/(.*)(\n.*\n)(.*)/\3\2\1/}

复制代码