求取出关键字的正则表达式

jeffinier

[{u'hosts': [{u'hostid': u'18102'}], u'groupid': u'9'}, {u'hosts': [{u'hostid': u'18102'}], u'groupid': u'14'}, {u'hosts': [{u'hostid': u'18102'}], u'groupid': u'18'}, {u'hosts': [{u'hostid': u'18102'}], u'groupid': u'32'}]

如上的例子，我想取出所有关键字groupid后面的数字，想要输出：9,14,18,32...  但是groupid数量不定，可能是1个，3个或者多个，我的目的是有多少个就取多少个，然后打印出来， 怎么实现这样的正则呢？

baby_神

1. import re
   
2. x = "[{u'hosts': [{u'hostid': u'18102'}], u'groupid': u'9'}, {u'hosts': [{u'hostid': u'18102'}], u'groupid': u'14'}, {u'hosts': [{u'hostid': u'18102'}], u'groupid': u'18'}, {u'hosts': [{u'hostid': u'18102'}], u'groupid': u'32'}]"
   
3. print(re.findall(r'(?<=groupid).+?(\d+)',x))
   

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baby_神

1. echo "[{u'hosts': [{u'hostid': u'18102'}], u'groupid': u'9'}, {u'hosts': [{u'hostid': u'18102'}], u'groupid': u'14'}, {u'hosts': [{u'hostid': u'18102'}], u'groupid': u'18'}, {u'hosts': [{u'hostid': u'18102'}], u'groupid': u'32'}]" | grep -Po 'groupid.+?\K(\d+)'
   
2. 9
   
3. 14
   
4. 18
   
5. 32

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baby_神

1. x = [{u'hosts': [{u'hostid': u'18102'}], u'groupid': u'9'}, {u'hosts': [{u'hostid': u'18102'}], u'groupid': u'14'}, {u'hosts': [{u'hostid': u'18102'}], u'groupid': u'18'}, {u'hosts': [{u'hostid': u'18102'}], u'groupid': u'32'}]
   
2. print( [i.get('groupid') for i in x])
   
3. ['9', '14', '18', '32']

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