python怎么处理这种json格式的取值啊

jeffinier

从一个Http API中拿到的数据是json格式的，我只想打印出value的结果，像下面这样，
131-Li
132-Li
135-Li
160-Li
185-Li
...
...
...


{"API":{"locale":"en","version":"1.3","response":{"operation":{"name":"read","result":{"statuscode":"200","status":"Success","message":"Successfully fetched.","created-date":"Jan 6, 2017 06:57 PM"},"Details":{"field-names":{"name":{"type":"String","content":"Name"}},"field-values":{"totalRecords":"21","record":[{"value":"131-Li"},{"value":"132-Li"},{"value":"135-Li"},{"value":"160-Li"},{"value":"169-Li"},{"value":"185-Li"}]}}}}}}

MMMIX

回复 1# jeffinier

https://docs.python.org/3/library/json.html

Linux_manne

已经是json 了 那么久一层层挖吧......
如果你硬要暴力取 那就用函数去递归....

1. d = {"API":{"locale":"en", 'value': "haha"   ,"version":"1.3","response":{"operation":{"name":"read","result":{"statuscode":"200","status":"Success","message":"Successfully fetched.","created-date":"Jan 6, 2017 06:57 PM"},"Details":{"field-names":{"name":{"type":"String","content":"Name"}},"field-values":{"totalRecords":"21","record":[{"value":"131-Li"},{"value":"132-Li"},{"value":"135-Li"},{"value":"160-Li"},{"value":"169-Li"},{"value":"185-Li"}]}}}}}}
   
2. 
   
3. 
   
4. def res(d):
   
5.         if isinstance(d, dict) and 'value' in d.keys():
   
6.                 print (d['value'])
   
7. 
   
8.         if isinstance(d, (list, tuple)):
   
9.                 for item in d:
   
10.                         res(item)
    
11. 
    
12.         if isinstance(d, dict):
    
13.                 for k in d:
    
14.                         res(d[k])
    
15. 
    
16. res(d)
    

复制代码

仅供参考.....

bskay

print '\n'.join([i['value'] for i in b['API']['response']['operation']['Details']['field-values']['record']])