有如下一行文本，怎样匹配带%之前那个数字

junweitao

Missing power-critical nets (157 missing / 72119 total = 0% missing) :

想匹配到挨着%那个数字，怎么做？

wsh1981

echo "Missing power-critical nets (157 missing / 72119 total = 0% missing)" | awk -F'=' '{print $2}'| awk -F'%' '{print $1}'

junweitao

回复 2# wsh1981

能再求助一下Perl 命令吗？

sunzhiguolu

1. grep -Po '\d+(?=%)' f

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junweitao

回复 4# sunzhiguolu

大神回答的真是简单粗暴啊，哈哈，谢谢啦，

moperyblue

1. sed -r 's/.*= ([0-9]+)%.*/\1/'

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zy86416779

1. [root@CentOS_6 init.d]# echo "Missing power-critical nets (157 missing / 72119 total = 0% missing) :" | egrep -o "[0-9]{1,}%" | sed 's/%//'
   
2. 0
   
3. [root@CentOS_6 init.d]# echo "Missing power-critical nets (157 missing / 72119 total = 123% missing) :" | egrep -o "[0-9]{1,}%" | sed 's/%//'
   
4. 123

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jcdiy0601

1. echo "Missing power-critical nets (157 missing / 72119 total = 0% missing) :"|grep -Po "[0-9]+(?=%)"

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fh21_xuejinlian

echo " Missing power-critical nets (157 missing / 72119 total = 0% missing) :"| grep -oP '\d+(?=%)'

apsufhvk

echo 'Missing power-critical nets (157 missing / 72119 total = 10% missing) :' | grep -Eo '[0-9]+%' | awk -F'%' '{print $1}'