把所有文件名输出到一个文件里，求助

水中的晚秋

Win10 64bit 系统

有一个文件夹，里面有很多子文件夹，下面有很多文件。

想用Python把文件名（只要文件名，其它一概不要，比如，时间，大小，文件属性，文件目录等等）输出到一个文件比如，txt, 或者word.

求助

现在，Python3.6已经安装好了。



图是另外一个朋友给的，谁给解释一下。谢谢各位亲！

jason680

回复 1# 水中的晚秋

>>> help(os.walk)

Help on function walk in module os:

walk(top, topdown=True, onerror=None, followlinks=False)
    Directory tree generator.
   
    For each directory in the directory tree rooted at top (including top
    itself, but excluding '.' and '..'), yields a 3-tuple
   
        dirpath, dirnames, filenames
   
    dirpath is a string, the path to the directory.  dirnames is a list of
    the names of the subdirectories in dirpath (excluding '.' and '..').
    filenames is a list of the names of the non-directory files in dirpath.
    Note that the names in the lists are just names, with no path components.
    To get a full path (which begins with top) to a file or directory in
    dirpath, do os.path.join(dirpath, name).