sed中匹配后s命令中的变量包含左斜杠

o06v90o

数组:for j in ${strg[@]}doecho "j is j"done
结果：
j is :/xs/app/
j is :/XS/1_WEB/1_WEB/XSAPP/



vi data
xs_app_static_source:/xs/app/
em_app_static_source_jsp:/XS/1_WEB/1_WEB/XSAPP/




for j in ${strg[@]}
do
location=$(sed -n '/'${j//'/'/'\/'}'/p' data|cut -d: -f2)

sed  -i "/'${j//'/'/'\/'}'/{n;s~\([a-zA-Z]\+\)\([[:space:]]*\)\([^\;]*\)~\1\2$location\~}" nginx

done


$location怎么处理，里面包含左斜杠/，执行总是失败。

我想在nginx里面找到匹配的行，然后读取下一行，替换成$location

yinyuemi

回复 1# o06v90o

1. y=/b/
   
2. 
   
3. echo 'a/b/c/d
   
4. e/f/g' |sed -n '\#'$y'#p'
   
5. a/b/c/d
   

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info sed

'\%REGEXP%'
     (The '%' may be replaced by any other single character.)

     This also matches the regular expression REGEXP, but allows one to
     use a different delimiter than '/'.  This is particularly useful if
     the REGEXP itself contains a lot of slashes, since it avoids the
     tedious escaping of every '/'.  If REGEXP itself includes any
     delimiter characters, each must be escaped by a backslash ('\').

     The following two commands are equivalent.  They print lines which
     start with '/home/alice/documents/':

          sed -n '/^\/home\/alice\/documents\//p'
          sed -n '\%^/home/alice/documents/%p'
          sed -n '\;^/home/alice/documents/;p'

christmas1102

1. cat file
   
2. 1
   
3. 2
   
4. /var/
   
5. 4
   
6. 5
   
7. 1
   
8. 2
   
9. /var/
   
10. 4
    
11. 5

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1. var='/var2/'
   
2. sed -i '\@/var/@{n;s#.*$#'$var'#}' file
   

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1. cat file
   
2. 1
   
3. 2
   
4. /var/
   
5. /var2/
   
6. 5
   
7. 1
   
8. 2
   
9. /var/
   
10. /var2/
    
11. 5

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\%REGEXP% 大致就这意思吧

夏尾鱼

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