帮忙看看为什么报错？awk语法错误

hudong990616

_LETTERS_ONLY=`echo $1 | awk '{if($0 ~/[ ^a-z A-Z ]) print "1"}'`

错误代码
syntax error The source line is 1.
The error context is
                {if($0 ~/[ ^a-z A-Z ]) print >;>;>;  "1"} <<<
awk: The statement cannot be correctly parsed.
The source line is 1.
        awk: There is a missing } character.
        awk: There is a missing ) character.

lw371

你写错了，过滤条件需要放到{}之前的，比如：
_LETTERS_ONLY=`echo $1 | awk '/~[ ^a-z A-Z ]/{ print "1"}'`

xchen301

print要加{ }~
少了个/

你改成这样

1. _LETTERS_ONLY=`echo $1 | awk '{if($0 ~/[ ^a-z A-Z ]/) {print "1"}}'`

复制代码