bash shell problem

cs221313

Hi, all
I have a bash code as follows:
for divideLine in `grep -n '^End\ of' SimpleDraw`
do
        echo $divideLine
done

when I run this command: grep -n '^End\ of' SimpleDraw. the output is:
54:End of Canvas.cpp
91:End of Canvas.h
396:End of CommandParser.cpp
494:End of CommandParser.h
525:End of CommonTypes.h
543:End of Coordinate.cpp
557:End of Coordinate.h

but when I run the above bash code, it seperated the line as follows:
54:End
of
Canvas.cpp
91:End
of
Canvas.h
396:End
of
CommandParser.cpp

anybody can help me to solve this problem?

thanks so much.

寂寞烈火

看不懂E文的说~

寂寞烈火

1. 
   
2. IFS=
   
3. for divideLine in `grep -n '^End\ of' SimpleDraw`
   
4. do
   
5. echo $divideLine
   
6. done

复制代码

vic2005

What's the value of variable divideLine?