再显示前一天时间时，修改时间显示2005－3－7为2005－03－07

duanyg

month=`date +%m`
day=`date +%d`
year=`date +%Y`

# Add 0 to month. This is a
# trick to make month an unpadded integer.
#month=`expr $month + 0`

# Subtract one from the current day.
day=`expr $day - 1`

# If the day is 0 then determine the last
# day of the previous month.
if [ $day -eq 0 ]; then

  # Find the preivous month.
  month=`expr $month - 1`

  # If the month is 0 then it is Dec 31 of
  # the previous year.
  if [ $month -eq 0 ]; then
    month=12
    day=31
    year=`expr $year - 1`

  # If the month is not zero we need to find
  # the last day of the month.
  else
    case $month in
      01|03|05|07|08|10|12) day=31;;
      04|06|09|11) day=30;;
      02)
        if [ `expr $year % 4` -eq 0 ]; then
          if [ `expr $year % 400` -eq 0 ]; then
            day=29
          elif [ `expr $year % 100` -eq 0 ]; then
            day=28
          else
            day=29
          fi
        else
          day=28
        fi
      ;;
    esac
  fi
fi
# Print the month day and year.
data="$year-$month-$day"
day="$year$month$day"
echo $data

hawkli

虽然很长，虽然很罗嗦，不过在某些时候还是有点作用的。

locallocal

这个shell有问题，如果是10号的前一天，只会输出9，而不是09
日和月都要加这个判断
if [ $day -lt 10 ]
then
     day=0$day
fi
if [ $month -lt 10 ]
    then
        month=0$month
    fi

icesummit

如果有-d，直接写成这样
date -d "-yesterday" +%Y-%m-%d

寂寞烈火

又是一个月经贴