awk里如何这样行取记录

bkj

文件一、
1/257,1,0000000000000000,4450CA6CAF401B96,218.71.34.101,218.74.34.101,
1/257,1,0000000000000000,4450CA65AF401B63,218.72.34.101,218.74.34.101,
1/257,1,0000000000000000,4450CA66AF401B70,218.73.34.101,218.74.34.101,21
1/257,1,0000000000000000,4450CA6CAF401B9E,,218.74.34.101,218.74.34.101,
1/257,1,0000000000000000,4450C886AF401CDE,218.74.35.101,218.74.
1/257,1,0000000000000000,4450C7F9AF40185F,218.74.35.101,218.74.34.101,
1/257,1,0000000000000000,4450CA71AF401BBF,218.75.34.101,218.74.34.101,


对每个文件我要取第五列为218.74.34.101和218.74.35.101的行,如何通过awk进行过滤呢?并把过滤结果生成到薪文件里?
请各位好心的朋友帮忙看一下?

bkj

也就是过滤后的文件里的内容是:
1/257,1,0000000000000000,4450CA6CAF401B9E,,218.74.34.101,218.74.34.101,
1/257,1,0000000000000000,4450C886AF401CDE,218.74.35.101,218.74.
1/257,1,0000000000000000,4450C7F9AF40185F,218.74.35.101,218.74.34.101,

bkj

cat bank-1-20060427214337.cdr | awk -F "," 'if(substr($5,1,7)=="218.74.") {print $0}'
这样写错在哪呢?

heyist

if 条件放到大括号里面试试

ruson

看看我的总结就知道了，呵呵
if必须放在{}中间，也就是必须在action中。