一個挺有趣的簡單小游戲.

eookoo

感覺最近這裡冷清了很多,所以給大家一個小游戲動動腦根.. =]

前幾天在一個 blog 上看到了一個有趣的簡單小游戲.
游戲說明:
1) 電腦隨機給出 1 到 9 不順序的 list  ---> [2,3,6,8,1,9,4,7,5] (for example)
玩法:
2 3 6 8 1 9 4 7 5
Reverse how many? 6
9 1 8 6 3 2 4 7 5
Reverse how many? 9
5 7 4 2 3 6 8 1 9
Reverse how many?
..........
2 1 3 4 5 6 7 8 9
Reverse how many? 2
Done! That took you 12 steps.

大家明白了嗎.....寫出這游戲吧...
過幾天我會 post 我的 code 上來.....

gosman

我的代码，欢迎指教。这个小游戏是有规律的哦，最多只要15步，玩的时候超过的话，就要好好想想了

#!/usr/bin/env python # File: numgame.py # Author: gosman # Date: 2007-7-15 import random step = 0 numarray = range(1,10) list = range(1,10) random.shuffle(list) while not(list == numarray):     for i in range(9):         print list[i],     step = step + 1     index = raw_input('\nReverse how many? ')     index = int(index)     tmp = list[0:index]     tmp.reverse()     list = tmp + list[index:] print 'Done ! That took you %d steps.' % step

eookoo

呵呵....終於有人來了..xD...!!

Gosman 你的 code 當然是沒錯...
但有沒有想過,只用不多於 10 行的 code 來寫(ofcause # not count as a line)??

pth

用python的函数式编程能力
也许能用不多于10 行的 code 來写

eookoo

以下是我的 code , 多多指教, 不知道可以不可以再精簡一點!!

import random # generate a list of numbers 1-9 in random order # for instance: [3,5,7,1,2,9,6,8,4] numbers = random.sample(range(1,10), 9) steps = 0 # numerbs != [1,2,3,4,5,6,7,8,9] while numbers != range(1,10):     # join the all 9 numbers together with a space     # for instance: 2 9 3 6 1 8 7 5 4     # or use  ' '.join( str(n) for n in numbers )     print ' '.join(map(str,numbers))     index = int(raw_input('Reverse how many? '))     # here is the main part of the game.     # index-1 is the range of the numbers you select,     # and -1 is to reverse the selected numbers.     numbers[:index] = numbers[index-1::-1]     steps += 1     print 'Done! That took you %d steps.' % steps

[ 本帖最后由 eookoo 于 2007-7-17 00:20 编辑 ]

mysll

我觉得如果是为了写着玩缩短是可以的，不过一般写程序没必要写这么短
从效率上讲
while numbers != range(1,10):
这个效率应该比下面的差一点
temp=range(1,10)
while numbers==temp
个人意见～～～

pth

果然用了map
函数式编程里很重要的函数

mageguoshi

这条语句能不能解释一下呢

numbers[:index] = numbers[index-1::-1]

mageguoshi

自己试了一把,是把这部分数组倒转了一把!主要以前没用过::的用法!

eookoo

[::] 這個用法是在 cookbook 中找到的...
原文如下:

1. Strings are immutable, so, to reverse one, we need to make a copy. The simplest approach for reversing is to take an extended slice with a "step" of -1, so that the slicing proceeds backwards:
   
2. 
   
3. revchars = astring[::-1]
   

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