求正则表达式的写法，谢谢！

人面兽心

想提取某网页中指定域名的url, ？

比如网页中有如下内容：

<a href="http://www.163.com/news/rgh248/page12326.htm"><img src="1.jpg" width="90" height="67" border="1"></a>
<a href="http://www.163.com/news/rgh2343242/page126.htm"><img src="2.jpg" width="90" height="67" border="1"></a>
<a href="http://www.yahoo.com/aws/pa6.htm"><img src="3.jpg" width="90" height="67" border="1"></a>



我怎样才能把包含163.com的网址全部提取出来？

preg_match_all 该怎么写？

正则表达式真的晦涩难懂啊，头都大了，请高手赐教

redicaps

"http://www.163.com/[^"]+"

人面兽心

好像不行呀，
语法错误
<?php
$str="
<a href=\"http://www.163.com/news/rgh248/page12326.htm\"><img src=\"1.jpg\" width=\"90\" height=\"67\" border=\"1\"></a>
<a href=\"http://www.163.com/news/rgh2343242/page126.htm\"><img src=\"2.jpg\" width=\"90\" height=\"67\" border=\"1\"></a>
<a href=\"http://www.yahoo.com/aws/pa6.htm\"><img src=\"3.jpg\" width=\"90\" height=\"67\" border=\"1\"></a>";

preg_match_all("http://www.163.com/[^"]+",$str,$matches);

print_r ($matches);
?>

PHP Parse error:  syntax error, unexpected ']' in /test.php on line 7

redicaps

sorry

try this


preg_match_all('@http://www.163.com/[^"]+@i',$str,$matches);

人面兽心

Works great for me!
Thanks