文件123.txt 格式如下:
CHROM 100 101 102 103 104 105 106 107 108 109 10 110 111 112 113 114
1 1/1:0,0,0:3 1/1:0,0,0:3 1/1:0,0,0:3 1/1:0,0,0:3 1/1:0,0,0:3 1/1:8,6,0:7 1/1:0,0,0:3 1/1:46,6,0:8 1/1:0,0,0:3 1/1:0,0,0:3 1/1:0,0,0:3 1/1:0,0,0:3 1/1:0,0,0:3 1/1:0,0,0:3 1/1:0,0,0:3
2 0/0:0,0,0:9 0/0:0,0,0:9 0/0:0,0,0:9 0/0:0,0,0:9 0/0:0,0,0:9 0/0:4,3,0:8 0/0:0,0,0:9 0/0:0,6,46:15 0/0:0,0,0:9 0/0:0,0,0:9 0/0:0,0,0:9 0/0:0,0,0:9 0/0:0,0,0:9 0/0:0,0,0:9 0/0:0,0,0:9
3 0/0:0,0,0:10 0/0:0,0,0:10 0/0:0,0,0:10 0/1:40,3,0:13 0/0:0,0,0:10 0/0:0,3,4:13 0/0:0,0,0:10 0/0:0,6,46:16 0/0:0,0,0:10 0/0:0,0,0:10 0/0:0,0,0:10 0/0:0,0,0:10 0/0:0,0,0:10 0/0:0,0,0:10 0/0:0,0,0:10
4 0/0:0,0,0:10 0/0:0,0,0:10 0/0:0,0,0:10 0/0:0,3,40:13 0/0:0,0,0:10 0/0:0,3,4:13 0/0:0,0,0:10 0/0:0,6,46:16 0/0:0,0,0:10 0/0:0,0,0:10 0/0:0,0,0:10 0/0:0,0,0:10 0/0:0,0,0:10 0/0:0,0,0:10 0/0:0,0,0:10
5 0/0:0,0,0:6 0/0:0,0,0:6 0/0:0,0,0:6 0/0:0,3,40:8 0/0:0,0,0:6 0/0:4,3,0:5 0/0:0,0,0:6 0/1:46,6,0:6 0/0:0,0,0:6 0/0:0,0,0:6 0/0:0,0,0:6 0/0:0,0,0:6 0/0:0,0,0:6 0/0:0,0,0:6 0/0:0,0,0:6
6 1/1:0,0,0:6 1/0:0,0,0:6 1/0:0,0,0:6 1/0:0,3,40:9 1/0:0,0,0:6 1/0:0,3,4:8 1/0:0,0,0:6 0/1:0,6,46:11 0/1:0,0,0:6 1/1:0,0,0:6 1/1:0,0,0:6 1/0:0,0,0:6 0/1:0,0,0:6 0/0:0,0,0:6 0/0:0,0,0:6
如何统计每行出现的 0/0的次数,并把出现0/0次数大于8的行删除?请指教!谢谢!
统计完删除后的文本new。txt是这样的:
CHROM 100 101 102 103 104 105 106 107 108 109 10 110 111 112 113 114
1 1/1:0,0,0:3 1/1:0,0,0:3 1/1:0,0,0:3 1/1:0,0,0:3 1/1:0,0,0:3 1/1:8,6,0:7 1/1:0,0,0:3 1/1:46,6,0:8 1/1:0,0,0:3 1/1:0,0,0:3 1/1:0,0,0:3 1/1:0,0,0:3 1/1:0,0,0:3 1/1:0,0,0:3 1/1:0,0,0:3
6 1/1:0,0,0:6 1/0:0,0,0:6 1/0:0,0,0:6 1/0:0,3,40:9 1/0:0,0,0:6 1/0:0,3,4:8 1/0:0,0,0:6 0/1:0,6,46:11 0/1:0,0,0:6 1/1:0,0,0:6 1/1:0,0,0:6 1/0:0,0,0:6 0/1:0,0,0:6 0/0:0,0,0:6 0/0:0,0,0:6
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